findstr dos command need to exclude bytes free

From a win32 dos command box we can execute the dir command that shows the total free bytes on disk in the last line:

.....--output omitted--....
 Directory of C:\temp

21/10/2008  12:53    <DIR>          .
21/10/2008  12:53    <DIR>          ..
21/10/2008  12:53                 0 free.txt
               1 File(s)              0 bytes
               2 Dir(s)  142.985.986.048 bytes free


With the findstr command you can exclude string data from a command. I was trying to get the free bytes value from the last line 142.985.986.048 so i can put it in a variable.

Anyone that can help me a bit?

C:\>findstr /R "<<regular expression needed here>" |dir

more info on the findstr win32 command:
http://www.ss64.com/nt/findstr.html
techneitsolutionsAsked:
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ahoffmannCommented:
for /f "usebackq tokens=2,3,4" %i in (`dir`) do @if %k==bytes echo %j
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ahoffmannCommented:
> .. so i can put it in a variable.
for /f "usebackq tokens=2,3,4" %i in (`dir`) do @if %k==bytes set variable=%j
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techneitsolutionsAuthor Commented:
"k was unexcpected at this time"

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ahoffmannCommented:
then your dir command returns strange results, it works for the xample given in the initial question
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techneitsolutionsAuthor Commented:
Well i created two batch files:

example1.bat that holds the first post
example2.bat that holds the second post.

I executed both of them, see results in attached file...
batchfiles.jpg
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ahoffmannCommented:
> Well i created two batch ..
in batch files you have to double the %
read find help about stupid windoze syntax
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Regular Expressions

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