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How to check if value in a list in Perl?

Posted on 2008-10-21
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Last Modified: 2012-05-05
Hi,

I am trying to create a conditional statement "if" that will check if a value is in a list of values. Right now, I simply do this:

if ( $myvar == 'VAR0123' || $myvar == 'VAR1234' || $myvar == 'VAR2345' )
{
}

I would prefer to setup all my "values" in an array or hash at one place and then do something like:

if ( $myvar ISIN $mylist )
{
}

Can this be done easily in Perl? Maybe using a hash table? Any ideas?
0
Comment
Question by:bganoush
7 Comments
 
LVL 10

Expert Comment

by:MadShiva
ID: 22766921
Hi !


Maybe there is one better solution, but is one solution :


#!/usr/bin/perl

@list = (VAR0123,VAR1234,VAR2345);

foreach $i (@list)
{

          if ( $i == 'VAR0123')
          {

          }

}
0
 

Author Comment

by:bganoush
ID: 22767002

Nevermind.. I think I know what to do...

If I create a hash like this...
my %mylist = ('VAR0123' => 1, 'VAR1234' => 1, 'VAR2345' => 1);

then I simply check if the hash returns a value like this:

if ( $mylist{$myvar} )
{
}

Would that work?  Also, is it possible to do this if the hash names are only numeric?  example: instead of 'VAR1234', I have '000001234'....
0
 

Author Comment

by:bganoush
ID: 22767023

I wonder also...

What if I put all my values in a text array like this:

$mylist = '000000123 000001234 000002345';

I guess I can now use a regex to "find" the value?

0
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LVL 10

Expert Comment

by:MadShiva
ID: 22767241
Hi !


$mylist = '000000123 000001234 000002345';

@list = split(/ /, $mylist);

foreach $i (@list)
{

if($i=~ m/$myvar/)
            {
            print " is in ";
            }

}



OR



$mylist = '000000123 000001234 000002345';


if($mylist =~ m/$myvar/)
            {
            print " is in ";
            }


Best Regards
0
 
LVL 39

Expert Comment

by:Adam314
ID: 22768507
A hash will work if what you have is a number.  The key is always interpreted as a string though, so if you have a number, it will be interpreted as a string.

If you have a single string, and want to use a regex, you can do this.  Note that because this is processed as a string, the number '00123' is different from '0123' which is different from '123.0'.
$myvar = '000000123';

$mylist = '(000000123|000001234|000002345)';

if($myvar =~ /$mylist/) {

    print "myvar is in mylist\n";

}

else {

    print "myvar is NOT in mylist\n";

}

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LVL 84

Accepted Solution

by:
ozo earned 500 total points
ID: 22768951
generally, $mylist{$myvar} would be better for this kind of thing than grep or foreach or =~
$i == 'VAR0123'
will match anything that does not look like a number
0
 

Author Closing Comment

by:bganoush
ID: 31508242
Thanks.
0

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