Need to return the most recent sale for each salesman

I have the following data:

TableAutoID    SalespersonID  Sale Date
83                     388                       2008-10-03 12:43:25.320
84                     481                       2008-10-03 12:50:04.807
85                     481                       2008-10-03 12:51:01.150
86                   100                    2008-10-03 12:50:04.807
87                   100                    2008-10-03 12:43:25.320
... and so on, but that's enough to indicate what I need.


I need to return the TableAutoId of the most recent sale for each salespersonID, so based on the records shown above, I need to return 83, 85 and 86. I've gone round and round trying to find some way to do this in a query WITHOUT A CURSOR, and I think it can be done with some sort of correlated subquery selecting from an aliased version of the original table, but thus far, I haven't come up with the solution to what seems like a fairly common query. Thus, I have come to grovel at the feet of the experts at experts exchange. Grovel, grovel.
nedrich12Asked:
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jfmadorCommented:
Try this

SELECT TableAutoID FROM table
INNER JOIN
(SELECT SalesPersonID, MAX(SaleDate) as MAxSaleDate FROM table GROUP BY SalesPersonID) t
ON table.SalesPersonID = t.SalesPersonID and table.SaleDate = t.SaleDate
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HuyBDCommented:
try this
select * from utable
where [Sale Date]=(select max([Sale Date]) 
from utable as t where t.SalespersonID=utable.SalespersonID)

Open in new window

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jfmadorCommented:
Sorry i made a mistake

SELECT TableAutoID FROM table
INNER JOIN
(SELECT SalesPersonID, MAX(SaleDate) as MAxSaleDate FROM table GROUP BY SalesPersonID) t
ON table.SalesPersonID = t.SalesPersonID and table.SaleDate = t.MaxSaleDate

I mispelled a field from t
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nedrich12Author Commented:
Thanks for your help. This is exactly what I needed.
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