Need XSL code to skip output if a condition is met in a tag, again.

Gertone answered this question previously with the attached code.
This code has worked wonders for those tags that are empty or have differing amounts of characters in them.
I have finally stumbled upon a tag that will contain either an X or an N.  If it contains an X, that I have to skip that line from being printed.
I have tried variations of the following:
<xsl:if test="contains(normalize-space(Rtype01), X)">
and
<xsl:if test="match(normalize-space(RateTypeMinBill), X)">
Even if I get past the syntax errors, it just prints my line regardless.
  I think what I need to do is say something like, if test="match..... then call the normalize-space function but I am doing something(many things, all things) wrong.

Thanks in advance for any help.

<xsl:value-of select="$Line1_AppNumber"/>
        <xsl:value-of select="$nl"/>
        <xsl:if test="string-length(normalize-space(Rtype01)) > 0">
            <xsl:value-of select="$Line2_Rtype01"/>
            <xsl:value-of select="$nl"/>
        </xsl:if>
        <xsl:value-of select="$Line3_Rtype02"/>
        <xsl:value-of select="$nl"/>

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