Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

Enter values in one range based upon values in another range...

Posted on 2008-10-22
8
Medium Priority
?
151 Views
Last Modified: 2012-05-05
Whenever "(1)" [without " "] shows up in range AQ102:AQ141 I would like VBA code to enter 0 [zero] in the corresponding cell in range AQ59:AQ98.
0
Comment
Question by:ronadair
  • 4
  • 3
8 Comments
 
LVL 76

Accepted Solution

by:
GrahamSkan earned 2000 total points
ID: 22782097
Do you mean like this?
    Dim cl As Range
    For Each cl In ActiveSheet.Range("AQ102:AQ141").Cells
        If cl.Value = "(1)" Then
            cl.Offset(59 - 102, 0).Value = 0
        End If
    Next cl

Open in new window

0
 
LVL 17

Expert Comment

by:Daniel Reynolds
ID: 22782124
Your specs are a little vague, but if AQ102:AQ141 are text formatted cells, the following formula will provide the zero for the corresponding cell(s).

=IF(AQ102 = "(1)",0,"")
once you have entered the formula in cell AQ59, just select the cell and drag the lower right corner down thru cell AQ98. This will copy the formula to the remaining cells.
0
 

Author Comment

by:ronadair
ID: 22782144
Graham -

I tried the code but it won't execute.  The line
If cl.Value = "(1)" Then
is highlighted in yellow.

Division produces the values in AQ102:AQ141 & a few of them come up #DIV/0!.  Could this be screwing up the code?

Ron

0
What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

 
LVL 76

Expert Comment

by:GrahamSkan
ID: 22782168
Yes. I wasn't expecting that. Try cl.Text  instead of cl.Value.
0
 

Author Comment

by:ronadair
ID: 22782191
Graham -

I tried the change... still no cigar.  ;>(

Ron
0
 

Author Closing Comment

by:ronadair
ID: 31509002
Graham -
I got rid of the #DIV/0! error with the formula
=IF(OR(Y59=0,AB8=0),0,Y59/AB8)
Your solution now works.

Thanks.
0
 

Author Comment

by:ronadair
ID: 22785013
Graham -

I fixed the #DIV/0! issue & the code worked with a minor adjustment.  Back to cl.Value and "-1" rather than "(1)".

Thanks,

Ron
0
 
LVL 76

Expert Comment

by:GrahamSkan
ID: 22785443
Yes if you simply enter (1) into a cell, it is converted to -1, but if you enter '(1), you will get the text - less the apostrophe.
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Enums (shorthand for ‘enumerations’) are not often used by programmers but they can be quite valuable when they are.  What are they? An Enum is just a type of variable like a string or an Integer, but in this case one that you create that contains…
You can of course define an array to hold data that is of a particular type like an array of Strings to hold customer names or an array of Doubles to hold customer sales, but what do you do if you want to coordinate that data? This article describes…
Get people started with the process of using Access VBA to control Outlook using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Microsoft Outlook. Using automation, an Access applic…
Get people started with the utilization of class modules. Class modules can be a powerful tool in Microsoft Access. They allow you to create self-contained objects that encapsulate functionality. They can easily hide the complexity of a process from…
Suggested Courses

824 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question