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Remove first 5 and last 6 characters of string

Posted on 2008-10-23
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Last Modified: 2012-05-05
I need to write a stored procedure that will check the first 5 and last 6 charcters of a string.  If the first 5 characters = '<div>' and the last 6 = '</div>' i need to remove them from the string.  I need to loop this to remove multiple instances. i.e. if the string was '<div><div>some stuff here</div></div>' the result would be 'some stuff here'
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Question by:APhoenixRising
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Expert Comment

by:Binuth
ID: 22784364
declare @s as varchar(max)
set @s ='<div><div>some stuff here</div></div>'
set @s= replace(replace(@s,'<div>',''),'</div>','')
select @s
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Expert Comment

by:Binuth
ID: 22784371
if u r using MS SQL 2000 , change  varchar(max) to varchar(1000)
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Author Comment

by:APhoenixRising
ID: 22784382
Hi, this won't work as it will replace all occurences of <div> or </div>.  i only want to remove them if they are the first and last instances in the string.  i.e. if the string was: '<div><div>some <div> stuff </div>here</div></div>'
it would return: some <div> stuff </div>here
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Accepted Solution

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Binuth earned 2000 total points
ID: 22784420

declare @s as varchar(1000)
set @s ='<div><div>some stuff <div> here</div></div>'
 
while (left(@s,5)='<div>' or right(@s,6)='</div>')
begin
	if(left(@s,5)='<div>')
		set @s = substring(@s,6,len(@s)-5)
	else
		set @s = substring(@s,1,len(@s)-6)
end
select @s

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Author Closing Comment

by:APhoenixRising
ID: 31509135
Fantastic.  Many thanks
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