[Webinar] Streamline your web hosting managementRegister Today

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 627
  • Last Modified:

MS SQL 2005 Convert Vertical Data in Horizontical Row

Sir, I am using following statement to convert Vertical data in Horizontical Rows , but unable to understand error, please help

--Create Data Temp Table
Drop Table #UpdateReceiving

Create Table #UpdateReceiving (JobNo Varchar(25), VslNVoy Varchar(25), DiversionStation Varchar(25), Tonnage Numeric(18,3))
Insert Into #UpdateReceiving(JobNo, VslNVoy, DiversionStation, Tonnage)

Select      b.jobno,b.vslnvoy,a.DiversionStation,
            Tonnag=sum(pnweight)/1000
from IMPCDTCP a Join IMPCD b on a.jobno=b.jobno
Where b.AgentCode='041' and a.del='0' and a.DiversionStation<>''
group by b.jobno,b.vslnvoy,a.sectorOrder, a.Sector, a.DiversionStation
Order by b.jobno,b.vslnvoy,a.sectorOrder, a.Sector, a.DiversionStation

Create Unique Index XI_UpdateReceiving On #UpdateReceiving (jobno,vslnvoy,DiversionStation,Tonnage)

--Select * From #UpdateReceiving

---Create Distinct Head Table
Drop Table #Column
Create Table #Column (Ident Int Identity(0,1), DiversionStation Varchar(100))
Insert Into #Column(DiversionStation)
SELECT DISTINCT DiversionStation FROM #UpdateReceiving
ORDER BY DiversionStation
--Select * From #Column

Create Unique Index XI_Column on #Column (Ident, DiversionStation)

--Create Distinct Row Detail

Drop Table #Row
Create Table #Row (JobNo varchar(20))
Insert Into #Row(JobNo)
SELECT DISTINCT JobNo FROM #UpdateReceiving
order by jobno
--Select * From #Row

Create Unique Index XI_Row on #Row(JobNo)

Declare @ColumnIndex Int
Declare @MaxColumn Int
Declare @ColumnText Varchar(100)
Declare @Sql varchar(8000)


Select       @ColumnIndex=0,
      @MaxColumn=Max(Ident)
from #Column

--print @MaxColumn

While @ColumnIndex <= @MaxColumn
Begin
      Select @ColumnText=DiversionStation
      From #Column
      where @ColumnIndex = Ident


Select @SQL= 'ALTER TABLE #Row ADD ' + QUOTENAME(@ColumnText) + ' Numeric(18,3) Default 0'
Exec   (@SQL)

      SELECT @SQL =       'UPDATE #Row SET ' + QUOTENAME(@ColumnText) + ' = #UpdateReceiving.Tonnage
                     FROM #UpdateReceiving (INDEX(XI_UpdateReceiving), NOLOCK), #Column
                               WHERE #Row.JobNo = #UpdateReceiving.JobNo
                               AND #Column.DiversionStation = #UpdateReceiving.DiversionStation
                               AND #Column.Ident = ' + CAST(@ColumnIndex AS VARCHAR(12))
        EXEC  (@SQL)
--Print @SQL

--Select * from #Row

Select @ColumnIndex = @ColumnIndex + 1

End


Error:

Msg 1018, Level 15, State 1, Line 2
Incorrect syntax near 'INDEX'. If this is intended as a part of a table hint, A WITH keyword and parenthesis are now required. See SQL Server Books Online for proper syntax.
0
Mehram
Asked:
Mehram
1 Solution
 
momi_sabagCommented:
it seems that it is ok syntax wise
i would just try to add print statements in order to find the exact statement that causes the error
0
 
MehramAuthor Commented:
The above code is creating column correctly. However it is not inserting values into the columns, scren short attached. please help where i am doing mistake.
Image.bmp
0

Featured Post

Learn to develop an Android App

Want to increase your earning potential in 2018? Pad your resume with app building experience. Learn how with this hands-on course.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now