[Webinar] Streamline your web hosting managementRegister Today

  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 797
  • Last Modified:

Convert PHP script to C# or Javascript

The attached code snippet happens on load of the web page. Can anyone tell me how to convert it to Javascript or C#? Bascially, what I have done is loaded some list items in an array. Then, based on the current page, the HTML is created when the page loads.
// maybe you need to add the directory name(s) too
      $items = array(
          array("link"=>"php.html", "label"=>"PHP scripts"),
          array("link"=>"tut.html", "label"=>"Tutorial"),
          array("link"=>"css.html", "label"=>"CSS template"),
          array("link"=>"code.html", "label"=>"Code examples"));
      $menu = '';
      foreach ($items as $val) {
          if  ($_SERVER['SCRIPT_NAME'] == $val['link']) {
          $menu .= '<li><span>' .$val['label'].'</span></li>';
	  } else {
	  $menu .= '<li><a href="'.$val['link'].'" >'.$val	   ['label'].'</a></li>';
      echo $menu;

Open in new window

  • 2
3 Solutions
Ryan ChongCommented:
I saw your pages are in .html, so I decided to use javascript to generate the menu.
<script language="javascript">
	//Ver 1.0
	function getFileName(fpath, removeQueryingString, delimiter) {
		if (fpath==null) fpath = window.location.href;
		if (delimiter==null) delimiter = "/";
		var tmp = fpath;
		if (tmp.lastIndexOf("?") > -1) {
			tmp = tmp.substring(0,tmp.lastIndexOf("?"));		
		tmp = tmp.substring(tmp.lastIndexOf(delimiter)+1);
		if (removeQueryingString != null) {
			if (removeQueryingString) {
				var tmpArr = tmp.split("?");
				tmp = tmpArr[0];
		return tmp;
	function generateMenu() {
		var arrlink = new Array(3);
		var arrlabel = new Array(3);
		arrlink[0] = "php.html";
		arrlabel[0] = "PHP scripts";
		arrlink[1] = "tut.html";
		arrlabel[1] = "Tutorial";
		arrlink[2] = "css.html";
		arrlabel[2] = "CSS template";
		arrlink[3] = "code.html";
		arrlabel[3] = "Code examples";
		var menu = "";
		for (var i=0;i<arrlink.length;i++) {
			if  (getFileName() == arrlink[i]) {
				menu += "<li><span>" + arrlabel[i] + "</span></li>";
			} else {
				menu += "<li><a href='" + arrlink[i] + "'><span>" + arrlabel[i] + "</span></a></li>";
		return menu;

Open in new window

<asp:DropDownList ID="ddl" runat="server" />
// C# -- put this in your page_load
if (!IsPostBack)
    Dictionary<string, string> items = new Dictionary<string, string>();
    items.Add("php.html", "PHP scripts");
    items.Add("tut.html", "Tutorial");
    items.Add("css.html", "CSS template");
    items.Add("code.html", "Code examples");
    foreach (var item in items)
        ddl.Items.Add(new ListItem(item.Value, item.Key));

Open in new window

actually, I made that more complicated than I needed to, keep the same asp.net of:

<asp:DropDownList ID="ddl" runat="server" />

and put this in your codebehind:
    ddl.Items.Add(new ListItem("php.html", "PHP scripts"));
    ddl.Items.Add(new ListItem("tut.html", "Tutorial"));
    ddl.Items.Add(new ListItem("css.html", "CSS template"));
    ddl.Items.Add(new ListItem("code.html", "Code examples"));

Open in new window

computerstreberAuthor Commented:
both of these were awesome examples. However, I found the javascript to render much better.

Featured Post

2018 Annual Membership Survey

Here at Experts Exchange, we strive to give members the best experience. Help us improve the site by taking this survey today! (Bonus: Be entered to win a great tech prize for participating!)

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now