Solved

Only selecting 1 row in the db

Posted on 2008-10-24
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290 Views
Last Modified: 2013-12-13
How do i get this code to select the row in the db i click on. There is a button in each row which pops up a map but it only pops up row 1. i tried somthing like select * from table where id='id' somthing like that but didnt work. Here is the code.


<?php

$link = mysql_connect('localhost','root', 'password');

if($link && mysql_select_db('nexodom_test'))

  {

  $sql = "select * from tblbasicform";

  $res = mysql_query($sql);

  $row = mysql_fetch_array($res);
 

  $addr =

  'http://maps.google.com/staticmap?center='.$row[latitude].','.$row[longitude].'&zoom=12&size=400x400&key=ABQIAAAAgnVrcDn5i-V_BsqvXy3j8RRle8Rt1EK93-n5qGMjk9aCuGqlpBQ2sCqItCc79KzQksp90dVmLGk45w';
 

header("Expires: Thu, 01 Jan 1970 00:00:01 GMT");

header("Location: $addr");
 

//echo "We will call this URL: <b>$addr</b>";

//exit();

  }
 

echo 'Cannot connect to database';

?>

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Question by:Lee-Bartlett
  • 8
  • 6
14 Comments
 
LVL 3

Expert Comment

by:raminhos
ID: 22799015
Can you show the fields of yout database?

Is your id key ? is autoincrement ?
0
 

Author Comment

by:Lee-Bartlett
ID: 22799079
Yes id is auto and key, that popup.php is connected to this page.  the pop up works when a buttopn is clicked
<?php  require_once("includes/db_connection.php"); ?>
 

<html>
 

<head>
 

<script language='javascript' type='text/javascript'>

<!--

function openWindow() {

 popupWin = window.open('popup.php', 'popup',

'width=550,height=400,resizable=no,scrollbars=yes,toolbar=no,screenX=0,screenY=0,Top=0,Left=0')

}

// -->

</script>

</head>
 

<body onLoad="load()" onUnload="GUnload()" >

<table width="802" border="1" align="center" cellpadding="5" cellspacing="0" bordercolor="#000000">

  <tr>

    <td colspan="2" bgcolor="#0099FF"><p>&nbsp;</p>

    <p align="center" class="style1">Nexodom.com</p>      

    <p>&nbsp;</p></td>

  </tr>

  <tr>

    <td width="102" height="318" align="left" valign="top"><p><a href="index.html">Home</a><br>

        <a href="wifi.php">WIFI Hot Spots</a></p>

    </td>

    <td width="674" align="left" valign="top"><p align="center">WIFI Hot Spot List</p>

    

<?php
 

$sql = "SELECT * from tblbasicform";

$res = mysql_query($sql) or die(mysql_error());
 

echo "<table border=2>";

echo "<tr> <td>Name</td><td>Email</td><td>Buissnes Name</td><td>Location</td><td>Latitude</td><td>Longitude</td> <td>Free or Paid</td><td>New</td></tr>";

while($row = MYSQL_FETCH_ARRAY($res))

{
 

echo "<tr><td>".$row['name']."</td>";

echo "<td>".$row['email']."</td>";

echo "<td>".$row['buissnes_name']."</td>";

echo "<td>".$row['location']."</td>";

echo "<td>".$row['latitude']."</td>";

echo "<td>".$row['longitude']."</td>";

echo "<td>".$row['type']."</td>";

echo "<form>";

echo "<td><input type=\"button\" onClick=\"openWindow(); return false;\" value=\"Pop Up Map\">";

echo "</td></tr>";

echo "</form>";
 

}

?>
 
 
 
 

</table><br>

<a href="userform.php">Submit a WIFI hotspot</a>

<br />

<br />
 

</body>

</html>

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LVL 3

Expert Comment

by:raminhos
ID: 22799234
Try this change your openwindow java to send id variable..

Then select * from table where id = $id


<script language='javascript' type='text/javascript'>

<!--

function openWindow() {

 popupWin = window.open('popup.php?id=<?=$id?>', 'popup',

'width=550,height=400,resizable=no,scrollbars=yes,toolbar=no,screenX=0,screenY=0,Top=0,Left=0')

}

// -->

</script>

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Author Comment

by:Lee-Bartlett
ID: 22799405
That broke the popup window
0
 

Author Comment

by:Lee-Bartlett
ID: 22799430
Maybe i need to do a $_GET? to get the longitude, latitude and ID oveR?
0
 
LVL 3

Expert Comment

by:raminhos
ID: 22799449
Check this answer i gave:

http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/Q_23842891.html?cid=236#a22792201

i show an example:


<?php

 

// your code...

 

?>

 

<script> 

function abrir()

{

window.open('http://google.com/<?=$images?>','Google','toolbar=no','directories=no','status=no','menubar=no','location=no','status=no','resizable=yes');

};

</script>

 

<?php

 

echo "<form>";

echo "<td><INPUT type='submit' name=submit value='New Window' onclick="abrir()";>";

echo "</td></tr>";

echo "</form>";

 

?> 

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Expert Comment

by:raminhos
ID: 22799452
And yes...depending of your php.ini configuration, you might need to use $_GET
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Author Comment

by:Lee-Bartlett
ID: 22799470
The window opens again, i need to know where im going wrong that it is only selecting only 1 row the first one.  
0
 
LVL 3

Expert Comment

by:raminhos
ID: 22799538
I don't understand what you want..

When user clicks the fomr button you open popup.php..

What should popup.php show ?

Google map with coordinates that you get from your databse ?
0
 

Author Comment

by:Lee-Bartlett
ID: 22799611
Yes, take a look at the site...

www.nexodom.com/website/wifi.php
0
 
LVL 3

Accepted Solution

by:
raminhos earned 500 total points
ID: 22799838
OK. i did something like that..

I needed to open a popup depending the button the user clicked.

In your case you need to send the id of the database row you want to get the coordinates, right ?

Didn't test the code..but..


<?php  require_once("includes/db_connection.php"); ?>
 

<html>
 

<body onLoad="load()" onUnload="GUnload()" >

<table width="802" border="1" align="center" cellpadding="5" cellspacing="0" bordercolor="#000000">

  <tr>

    <td colspan="2" bgcolor="#0099FF"><p> </p>

    <p align="center" class="style1">Nexodom.com</p>

    <p> </p></td>

  </tr>

  <tr>

    <td width="102" height="318" align="left" valign="top"><p><a href="index.html">Home</a><br>

        <a href="wifi.php">WIFI Hot Spots</a></p>

    </td>

    <td width="674" align="left" valign="top"><p align="center">WIFI Hot Spot List</p>
 

<?php
 

$sql = "SELECT * from tblbasicform";

$res = mysql_query($sql) or die(mysql_error());
 

echo "<table border=2>";

echo "<tr> <td>Name</td><td>Email</td><td>Buissnes Name</td><td>Location</td><td>Latitude</td><td>Longitude</td> <td>Free or Paid</td><td>New</td></tr>";

while($row = MYSQL_FETCH_ARRAY($res))

{

$id = $row['id'];

?>

<script language='javascript' type='text/javascript'>

<!--

function openWindow<?=$id?>() {

 popupWin = window.open('popup.php?id=<?=$id?>', 'popup','width=550,height=400,resizable=no,scrollbars=yes,toolbar=no,screenX=0,screenY=0,Top=0,Left=0')

}

// -->

</script>

<?

echo "<form method=post name=pop$id>";

echo "<tr><td>".$row['name']."</td>";

echo "<td>".$row['email']."</td>";

echo "<td>".$row['buissnes_name']."</td>";

echo "<td>".$row['location']."</td>";

echo "<td>".$row['latitude']."</td>";

echo "<td>".$row['longitude']."</td>";

echo "<td>".$row['type']."</td>";

echo "<form>";

echo "<td><input type=\"button\" onClick=\"openWindow$id(); return false;\" value=\"Pop Up Map\">";

echo "</td></tr>";

echo "</form>";
 

}

?>
 
 
 
 

</table><br>

<a href="userform.php">Submit a WIFI hotspot</a>

<br />

<br />
 

</body>

</html>

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LVL 3

Expert Comment

by:raminhos
ID: 22799849
Of course in popup.php you must do another select * from table where id = $id

You might need to do first: $id = $_GET['id'];

and then redirect with the coordinates you retrieve from database
0
 

Author Comment

by:Lee-Bartlett
ID: 22799934
That works great :D ill reveiw the code and see where i went wrong :) ty
0
 
LVL 3

Expert Comment

by:raminhos
ID: 22799961
Glad i could help :)
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