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Java XML to XML conversion

I have an XML input in the format:
      <attr name="field1name">
      <attr name="field2name">
      <attr name="field3name">


I want to transform it to look like this:


I can make an XSL/XSLT using my XML editor, but what is the simpest and most lightweight method to perform this transformation?  My app mainly uses jclark and javax libs.

Thanks for any advice :)
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1 Solution
Bryan ButlerCommented:
Xerces2 is a good way to do it.  Are you wanting specific code?  Specifically for JAXP?
ChrisOz2008Author Commented:
Looking for something more specific, don't really have the time study all the Xerces docs right now as this is a tiny portion of my project.
Kevin CrossChief Technology OfficerCommented:
The javax.xml API has a transformation portion to it.  See here for reference:

Using JDOM and XSLT

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ChrisOz2008Author Commented:
OK I almost got there.

Here is wha tI ended up with :

    String data = [0];
    String stylesheetname = "c:\\temp\\ant\\test5\\xml\\test.xsl";
    File stylesheetFile = new File(stylesheetname);
    String resultFile = "c:\\temp\\ant\\test5\\xml\\testout2.xml";
    Parser parser = createParser();
    XSLProcessor processor = new XSLProcessorImpl();
    processor.loadStylesheet(new InputSource(new BufferedReader(new FileReader(stylesheetname))));
    OutputMethodHandlerImpl outputMethodHandler = new OutputMethodHandlerImpl(processor);
    FileDestination dest = new FileDestination(resultFile);
    dest.getOutputStream("xml", "UTF-8");

Instead of the output going to file I need it to go out to a string or Document.
Kevin CrossChief Technology OfficerCommented:
Did you see the Xalan J information from IBM site I linked too?  It outputs to an XML Document object?

I will take a look at what you have...
Kevin CrossChief Technology OfficerCommented:
I think you would use OutputDocumentHandler from the JClark API instead of the OutputMethodHandler to get a Document (Destination) versus a file.
ChrisOz2008Author Commented:
I looked at this method and it requires  parser as a parameter, not sure how that gets me an output of a Document object.

Sorry I'm very dumb at XML stuff.  I'm surprised this is not a more common thing peiple want to do, read some xml in from a data stream, transform it using an XSL and output as a new data stream... what do other people do? Output it to a file?  But that seems very inefficient.. if I have a servlet for example and I have an incoming XML post which is some odd format, I transform it then process it. If i have to transform it out to file then read the file back before using my shiney newly structured XML that seems very inefficient.

Can anyone answer this question fully? 300 point to anyone that can.
Kevin CrossChief Technology OfficerCommented:
Well it was answered above using JDOM and XSLT (Xalan); however, you are trying to use JClark.  Hopefully someone else knows how to better explain JClark way as I am not as familiar with that.  According to the API though, you use the org.xml.sax.DocumentHandler which serializes to a Destination object which it is using to represent generic XML Document from my reading.  More detail than that is beyond me, sorry.  Not sure if this is what you are referring to as taking parser, but this is what I was pointing to.

public void setDocumentHandler(org.xml.sax.DocumentHandler handler)


// method you are currently using
public void setOutputMethodHandler(OutputMethodHandler handler)
ChrisOz2008Author Commented:
Aaaah :)   Suddenly my mind has clicked over and I can see what you're trying to tell me. I got it sorted now in about 5 lines of code. Thanks so much for persisting with my brain failure :)

I forgot to up my point assignment in my last response so I have done so here, if you reply me back I'll accept it.

Kevin CrossChief Technology OfficerCommented:
Which comment fixed it for you - http:#22808587?

Or http:#22822024?

Just to clarify for future readers. :)
ChrisOz2008Author Commented:
The last one. I had focussed on th JDOM reference which I had used before and found to be not quite what  iwas after. After you mentioned Xalan again I googled and found a really nice sample. My XML tool XMLBluePrint can take th input XML and the output I want and create me an XSL so even an XML dubass like me can get things working.

Thanks again for your advice!

Here is what I ended up with :

import javax.xml.transform.TransformerFactory;
import javax.xml.transform.Transformer;
import javax.xml.transform.stream.StreamSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerConfigurationException;

import java.io.FileOutputStream;
import java.io.FileNotFoundException;
import java.io.IOException;

public class XmlToXmlConvertor
   private TransformerFactory tFactory;
   private Transformer transformer;
   String stylesheetname = "c:\\temp\\ant\\test5\\xml\\test.xsl";
   String inFile = "c:\\temp\\ant\\test5\\xml\\in.xml";

  public static void main(String[] args) throws TransformerException, TransformerConfigurationException, FileNotFoundException, IOException
    // Use the static TransformerFactory.newInstance() method to instantiate a TransformerFactory. The javax.xml.transform.TransformerFactory
    // system property setting determines the actual class to instantiate -- org.apache.xalan.transformer.TransformerImpl.

    XmlToXmlConvertor xmlToXmlConversion = new XmlToXmlConvertor();


  public void performTransformation() throws TransformerException, TransformerConfigurationException, FileNotFoundException, IOException
    tFactory = TransformerFactory.newInstance();
    StringOutputStream sos = new StringOutputStream();

    // Use the TransformerFactory to instantiate a Transformer that will work with the stylesheet you specify. This method call also processes the stylesheet into
   // a compiled Templates object.

    transformer = tFactory.newTransformer(new StreamSource(stylesheetname));
    transformer.transform(new StreamSource(inFile), new StreamResult(sos));
    System.out.println("Output Start");
    System.out.println("Output End");
Kevin CrossChief Technology OfficerCommented:
Very nice!
Thanks for your patience.  You thanked me for sticking with you, but you stuck with me too and hopefully got a good working solution out of it.

Happy coding.


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