Solved

PHP Dir List To Dropdown

Posted on 2008-10-26
2
272 Views
Last Modified: 2013-12-13
Hello Experts,

I have a PHP Script to read a Directorys contents which then makes a Drop Down selection of the files, the only problem with the script is it displays the . and .. directory structure links in the drop down which i dont want, i just want the files from the directory displayed, I have no idea how to get these out of the drop down...

Script is below.

Thanks,
Steve
<?php 

if ($handle = opendir('../files')) { 

    echo "<label><select name=\"URL\" id=\"URL\" >"; 

    while (false !== ($file = readdir ($handle))) { 

        echo "<option value=\"$file\">$file</option>"; 

    } 

    echo "</select></label>"; 

    closedir($handle); 

} 

?>

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0
Comment
Question by:robsons995
2 Comments
 
LVL 8

Accepted Solution

by:
fcardinaux earned 500 total points
ID: 22806865

<?php 

if ($handle = opendir('../files')) { 

    echo "<label><select name=\"URL\" id=\"URL\" >"; 

    while (false !== ($file = readdir ($handle))) { 

        if ('.' === $file ¦¦ '..' === $file) continue;

        echo "<option value=\"$file\">$file</option>"; 

    } 

    echo "</select></label>"; 

    closedir($handle); 

} 

?>

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0
 

Author Comment

by:robsons995
ID: 22806891
I was getting an error with the above script "Parse error: syntax error, unexpected T_STRING in..."

Changed to the one below and it works fine now, thanks for your quick and accurate help!!! :-)

Steve.
if ($handle = opendir('../files)) { 

    echo "<label><select name=\"URL\" id=\"URL\" >"; 

    while (false !== ($file = readdir ($handle))) { 

        if ('.' === $file) continue;

        if ('..' === $file) continue;

        echo "<option value=\"$file\">$file</option>"; 

    } 

    echo "</select></label>"; 

    closedir($handle); 

} 

?>

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0

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