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xquery - how to use a recurring value only once

Posted on 2008-10-26
3
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Last Modified: 2013-11-11
I have a XML like this

<root>
<records>
<action id="1" site="A" item="abs"/>
<action id="2" site="A" item="hgt"/>
<action id="3" site="A" item="98uuj"/>
</records>
</root>

I want to make it into this one, where the site attribute will only appear once.
must use XQuery ...

<actions>
<site>A</site>
<items>
<item>
<id>1</id>
<code>abs</code>
</item>
<item>
<id>2</id>
<code>hgt</code>
</item>
<item>
<id>3</id>
<code>98uuj</code>
</item>
</items>
</actions>

0
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Question by:shalomc
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3 Comments
 
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Accepted Solution

by:
Geert Bormans earned 500 total points
ID: 22807208
mmh, it sounds like this is more a task for XSLT instead of XQuery, but here you go
let $doc := doc("file:///d:/untitled1.xml")
return
<actions>
    {
        for $a in distinct-values($doc//action/@site)
        return 
            <site>{$a}</site>
    }
    {
        for $a in distinct-values($doc//action/@site)
        return 
            <items>
                {
                for $b in $doc//action
                where $b/@site = $a
                return
                    <item>
                        <id>{string($b/@id)}</id>
                        <code>{string($b/@item)}</code>
                    </item>
                }
               </items>
    }
</actions>

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LVL 60

Expert Comment

by:Geert Bormans
ID: 22807221
in case you are interested, this is the XSLT you would need
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
    <xsl:output indent="yes"/>
    <xsl:template match="records">
        <actions>
            <xsl:for-each-group select="action" group-by="@site">
                <site><xsl:value-of select="@site"/></site>
                <items>
                    <xsl:for-each select="current-group()">
                        <item>
                            <id><xsl:value-of select="@id"/></id>
                            <code><xsl:value-of select="@item"/></code>
                        </item>
                    </xsl:for-each>
                </items>
            </xsl:for-each-group>
        </actions>
    </xsl:template>
</xsl:stylesheet>

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LVL 33

Author Comment

by:shalomc
ID: 22807500
the distinct-value had me going :)
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