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Java is zero-based, so if you have an XML string that is like this <br />
<br />
&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; standalone=&quot;no&quot;?&gt;<br />
&lt;root&gt;Hello World!&lt;/root&gt;<br />
<br />
Then the ?xml starts at index 1 NOT 2.<br />
<br />
Try this:<br />
if (xml.startsWith(&quot;?xml&quot;, 1))
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Java is zero-based, so if you have an XML string that is like this

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<root>Hello World!</root>

Then the ?xml starts at index 1 NOT 2.

Try this:
if (xml.startsWith("?xml", 1))

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mwvisa1, I considered that, and none work. &nbsp;Any other thoughts?
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mwvisa1, I considered that, and none work.  Any other thoughts?

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Please show me your String as that worked for me.
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Please show me your String as that worked for me.

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I do not have the problem now. &nbsp;I think the .trim() was what was missing.<br />
I got a question about an extra space that I am getting. &nbsp;If you have the time to add your comments, I would appreciate it.
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I do not have the problem now.  I think the .trim() was what was missing.
I got a question about an extra space that I am getting.  If you have the time to add your comments, I would appreciate it.

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Hello,<br />
I am using if (line.startsWith(&quot;?xml&quot;, 2)) { &nbsp;and it is not finding ?xml within the String.<br />
Any suggestions as to why it is not finding the substring?
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Hello,
I am using if (line.startsWith("?xml", 2)) {  and it is not finding ?xml within the String.
Any suggestions as to why it is not finding the substring?

line.startsWith

Java is a platform-independent, object-oriented programming language and run-time environment, designed to have as few implementation dependencies as possible such that developers can write one set of code across all platforms using libraries. Most devices will not run Java natively, and require a run-time component to be installed in order to execute a Java program.