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PowerShell: Combining arrays

Posted on 2008-10-28
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Last Modified: 2012-08-13

I have a little function, it has a daft name, but I never was any good at thinking of those. It accepts an object as input and returns a Byte Array. I use it to combine several different Byte Arrays into a one (the end result being a byte array I can send with the UDPClient).

Does anyone happen to know if there a quicker / simpler way of doing this?

The return value is modified to maintain the value type, without it implicitly converts to an Object type (my thanks go to MoW for that one).

Chris
function BuildCompositeArray ($Object) {
  # Returns Byte Array for referenced object
 
  $i = 0; $ByteArray = New-Object Byte[] ($Object.Count);
  ForEach ($Byte in $Object) {
    $ByteArray[$i] = $Byte; $i++;
  }
  # Stop implicit conversion to Object
  Return @(,$ByteArray);
}

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Question by:Chris Dent
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3 Comments
 
LVL 18

Accepted Solution

by:
BSonPosh earned 500 total points
ID: 22821764
You coulda emailed me directly :)

You can simply do this

function foo{
[Byte[]]$ByteArray = @()
foreach($byte in $input){$ByteArray += $byte}
$ByteArray
}

Then pipe the data into the function
32,53,33,51,22 | foo

BTW... below is my WOL script
function SendWOL{
    param ($macaddy)
    $mymac = $macaddy.split(':') | %{ [byte]('0x' + $_) }
    if ($mymac.Length -ne 6)
    {
        throw 'Mac Address Must be 6 hex Numbers Separated by : or -'
    }
    Write-Verbose "Creating UDP Packet"
    $UDPclient = new-Object System.Net.Sockets.UdpClient
    $UDPclient.Connect(([System.Net.IPAddress]::Broadcast),4000)
    $packet = [byte[]](,0xFF * 6)
    $packet += $mymac * 16
    Write-Verbose ([bitconverter]::tostring($packet))
    [void] $UDPclient.Send($packet, $packet.Length)
    Write-Host  "   - Wake-On-Lan Packet of length $($packet.Length) sent to $mymac"
}

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Author Comment

by:Chris Dent
ID: 22822249

I thought it might be more complicated than that and didn't want to impose :)

That simplifies most things actually. I hadn't figured out why my attempt to cast with [Byte]$Object wasn't working, that extra [] to declare it as an array makes so much difference :) Less code is good.

Passes the time, and gives me silly things to blog about, PowerShell is such a lot of fun :)

Chris
0
 
LVL 71

Author Closing Comment

by:Chris Dent
ID: 31510658
Thank you :)
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