chudmarek
asked on
Double.Parse C#
Hi Guys,
Hopefully an easy one.
I'm parsing two strings and converting them to doubles using double.Parse .
For example,
string1 = 2.32;
string2 = 2.37.
So i use if( double.Parse(string2) >Â double.Parse(string1)
{
//do something
}
The problem occurs, very rarely, that it will still go into "do something" even if string2 is not greater than string1. My values usually aren't so close....by that i mean that string1 and string2 values could be a lot further apart. So i'm wondering if there is any way that the double.Parse is rounding anything off, so when the values are too close like in the example above the statement holds true.
Thanks.
Hopefully an easy one.
I'm parsing two strings and converting them to doubles using double.Parse .
For example,
string1 = 2.32;
string2 = 2.37.
So i use if( double.Parse(string2) >Â double.Parse(string1)
{
//do something
}
The problem occurs, very rarely, that it will still go into "do something" even if string2 is not greater than string1. My values usually aren't so close....by that i mean that string1 and string2 values could be a lot further apart. So i'm wondering if there is any way that the double.Parse is rounding anything off, so when the values are too close like in the example above the statement holds true.
Thanks.
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as I know, there no function u want,
so u'll write it by yourself,
It's may help u,
so u'll write it by yourself,
It's may help u,
private void button2_Click(object sender, EventArgs e)
{
string string1 = "2.32";
string string2 = "2.37";
double d1 = double.Parse("2.321");
double d2 = double.Parse("2.376");
d1 = Truncate(d1, 2);
d2 = Truncate(d2, 2);
if (d2 > d1)
{
// Do
}
}
private double Truncate(double val, int de)
{
double dval = val*(Math.Pow(10,de));
dval = Math.Round(dval);
return dval / Math.Pow(10, de);
}SOLUTION
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ASKER
I thought that double should stay as the exact number...it is just strange.
Jandromeda, I can't give two values because the values are always changing and no two values are ever the same.