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How do I echo the results of the SELECT statement?

Posted on 2008-10-28
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Last Modified: 2013-12-13

I need to echo the results of the categories/subcategories below.  I am having trouble with the correct select statement.

Thanks for any assistance you can give me!!



<?php


$sql = "SELECT DISTINCT category FROM ddcart_products";
$result = mysql_query($sql) or die('Error: '.mysql_error());
echo '<option value="">- Pick a Category -</option>';
while($data = mysql_fetch_assoc($result)) {
  echo '<option value="'.$data['category'].'">'.$data['category'].'</option>';
 $sql2 = "SELECT DISTINCT subcategory FROM ddcart_products
           WHERE category = '{$data['category']}'";
  $result2 = mysql_query($sql2) or die('Error: '.mysql_error());
  if(mysql_num_rows($result2)>0) {
    /*echo '<optgroup>'*/;
    while($data2 = mysql_fetch_assoc($result2))
      echo '<option value="'.$data2['subcategory'].'">- ' .
           $data2['subcategory'].'</option>';
    echo '</optgroup>';
  }
}

  echo $res;
?>
</select> <input type="submit" value="Go"></form></div>
<div class="clear" style="height: 1px;"></div>
</div>

        <div class="clear" style="height: 1px;"></div>

    <?php

            //number of items per page
            $numitems = getOptionValue('itemsperpage');

            if(isset($_GET['page'])) {
                    $page = $_GET['page'];
                } else {
                        $page = 0;
                }
            //determine offset
            $offset = $page*$numitems;


//    NEED HELP GETTING RESULTS


                $sql = "SELECT * FROM ddcart_products WHERE category = ".$res." LIMIT ".$offset.", ".$numitems;
                $result = mysql_query($sql);
                $i = 1;
                while($data = mysql_fetch_assoc($result)) {
                        ?>
            <div class="productblock draggablediv" product="<?php echo $data['id'].'|'.$data['name'].'|'.$data['price']; ?>">
                    <div class="pbimage">  <img width=150 src="<?php echo $data['photourl']; ?>">   <!--<?php echo displayProductImage($data['id'], 'thumb'); ?>--></div>
                <div class="pbinfo"><a href="productdetail.php?product=<?php echo $data['id']; ?>" class="detailslink">View Details</a></div>
                <div class="pbtitle"><?php echo stripslashes($data['name']); ?></div>
                <div class="pbprice"><?php echo "$".number_format($data['price'], 2, '.', ','); ?></div>
            </div>
            <?php

            if(($i % 4) == 0) echo '<div class="clear"></div>';

            $i++;


                }

                echo '<div class="clear"></div><div id="pagenums" style="text-align: center;">';

                //total number of pages
                $sql = "SELECT * FROM ddcart_products WHERE cat = '".$cat."'";
                $result = mysql_query($sql);
                $numpages = floor(mysql_num_rows($result)/$numitems);

                for($i = 1; $i <= $numpages; $i++) {
                        if($page == $i) {
                                echo '<strong><span style="font-size: 12px; text-decoration: underline;"><a href="index.php?cat='.$cat.'&page='.$i.'">'.$i.'</a></strong>';
                        } else {
                                echo '<a href="index.php?cat='.$cat.'&page='.$i.'">'.$i.'</a>';
                        }

                }

                echo '</div>';

        ?>
0
Comment
Question by:rlb1
  • 5
  • 3
  • 3
11 Comments
 
LVL 82

Expert Comment

by:hielo
ID: 22827972
try:
<?php 
$sql = "SELECT DISTINCT category FROM ddcart_products";
$result = mysql_query($sql) or die('Error: '.mysql_error());
if( 1 > mysql_num_rows($result) )
{
	echo "No Categories Found!";
}
else
{
	echo "<select name='category'>";
	echo '<option value="">- Pick a Category -</option>';
	while($category = mysql_fetch_assoc($result))
	{
		$sql2 = "SELECT DISTINCT subcategory FROM ddcart_products WHERE category = '{$category['category']}'";
		$subcategory = mysql_query($sql2) or die(mysql_error());
		
		if( mysql_num_rows($subcategory) > 0)
		{
			echo "<optgroup label='{$category['category']}'>";
				while($subcat = mysql_fetch_assoc($subcategory) )
				{
					echo "<option value='{$subcat['subcategory']}'>{$subcat['subcategory']}</option>";
				}
			echo "</optgroup>";
		}
		else
		{
			echo "<option value='{$category['category']}'>{$category['category']}</option>";
		}
	}
	echo "</select>";
} 
?>

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0
 

Author Comment

by:rlb1
ID: 22828007
hielo,
Thanks for your help!!  I have found a solution to the Select drop down question, now I need to pull the items in each category and post them on my website using the code below..  

<?php

            //number of items per page
            $numitems = getOptionValue('itemsperpage');

            if(isset($_GET['page'])) {
                    $page = $_GET['page'];
                } else {
                        $page = 0;
                }
            //determine offset
            $offset = $page*$numitems;


//    NEED HELP GETTING RESULTS


                $sql = "SELECT * FROM ddcart_products WHERE category = ".$res." LIMIT ".$offset.", ".$numitems;    
                $result = mysql_query($sql);
                $i = 1;
                while($data = mysql_fetch_assoc($result)) {
                        ?>
            <div class="productblock draggablediv" product="<?php echo $data['id'].'|'.$data['name'].'|'.$data['price']; ?>">
                    <div class="pbimage">  <img width=150 src="<?php echo $data['photourl']; ?>">   <!--<?php echo displayProductImage($data['id'], 'thumb'); ?>--></div>
                <div class="pbinfo"><a href="productdetail.php?product=<?php echo $data['id']; ?>" class="detailslink">View Details</a></div>
                <div class="pbtitle"><?php echo stripslashes($data['name']); ?></div>
                <div class="pbprice"><?php echo "$".number_format($data['price'], 2, '.', ','); ?></div>
            </div>
            <?php

            if(($i % 4) == 0) echo '<div class="clear"></div>';

            $i++;


                }

                echo '<div class="clear"></div><div id="pagenums" style="text-align: center;">';

                //total number of pages
                $sql = "SELECT * FROM ddcart_products WHERE cat = '".$cat."'";
                $result = mysql_query($sql);
                $numpages = floor(mysql_num_rows($result)/$numitems);

                for($i = 1; $i <= $numpages; $i++) {
                        if($page == $i) {
                                echo '<strong><span style="font-size: 12px; text-decoration: underline;"><a href="index.php?cat='.$cat.'&page='.$i.'">'.$i.'</a></strong>';
                        } else {
                                echo '<a href="index.php?cat='.$cat.'&page='.$i.'">'.$i.'</a>';
                        }

                }

                echo '</div>';

        ?>
0
 
LVL 82

Expert Comment

by:hielo
ID: 22828046
Well that was not useful feedback. Not clear what the problem is.
0
 
LVL 82

Expert Comment

by:hielo
ID: 22828083
do you know if you are even getting any results? Try:

$sql = "SELECT * FROM ddcart_products WHERE category = ".$res." LIMIT ".$offset.", ".$numitems;

                $result = mysql_query($sql) or die(mysql_error() );
 

echo "Categories Found: " . mysql_num_rows($result);

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0
 
LVL 39

Expert Comment

by:Roger Baklund
ID: 22829353
$res has no value, it is a leftover from an earlier attempt in the Related Solution (ID:22826957).  
0
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LVL 39

Expert Comment

by:Roger Baklund
ID: 22829446
You probably want to list the products from the category selected in the dropdown? The below code will only work with categories, not with the sub-categories. You need to change the select dropdown to be able to list products within a sub-category.
if(isset($_POST['category'])) {

  $category = $_POST['category'];

  $sql = "SELECT * FROM ddcart_products WHERE category = ".$res." LIMIT ".$offset.", ".$numitems;    

  $result = mysql_query($sql);

  $i = 1;

  while($data = mysql_fetch_assoc($result)) {

    echo 

    '<div class="productblock draggablediv">'.

      '<div class="pbimage">'.

        '<img width=150 src="'.$data['photourl'].'" alt="" />'.

      '</div>'.

      '<div class="pbinfo"><a href="productdetail.php?product='.$data['id'].

        '" class="detailslink">View Details</a></div>'.

      '<div class="pbtitle">'.stripslashes($data['name']).'</div>'.

      '<div class="pbprice">$'.number_format($data['price'], 2, '.', ',').'</div>'.

    '</div>';

    if(($i % 4) == 0) 

      echo '<div class="clear"></div>';

      $i++;

  }

  echo '<div class="clear"></div><div id="pagenums" style="text-align: center;">';

  //total number of pages

  $sql = "SELECT count(*) FROM ddcart_products WHERE category = '".$category."'";

  $result = mysql_query($sql);

  $numpages = ceil(mysql_num_rows($result)/$numitems);

  for($i = 1; $i <= $numpages; $i++) {

    if($page == $i) {

      echo '<strong><span style="font-size: 12px; text-decoration: underline;">'.

           '<a href="index.php?category='.$category.'&amp;page='.$i.'">'.$i.'</a></strong>';

    } else {

      echo '<a href="index.php?category='.$category.'&amp;page='.$i.'">'.$i.'</a>';

    }

  }

  echo '</div>';

}

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LVL 39

Expert Comment

by:Roger Baklund
ID: 22829453
Sorry, line 3 should read:


  $sql = "SELECT * FROM ddcart_products WHERE category = '".$category."' LIMIT ".$offset.", ".$numitems;    

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LVL 39

Expert Comment

by:Roger Baklund
ID: 22829460
...and line 19 has wrong indentation, it is not part of the if in line 17/18.
0
 

Author Comment

by:rlb1
ID: 22831861
cxr, OK, I have a blank screen with no results.  Line 19 looks OK to me, how should it read?  Please clarify.  Does EE have private messaging?  Is there a way I can email you direct through EE?

Thanks!

Randy Bass  
0
 
LVL 39

Accepted Solution

by:
Roger Baklund earned 500 total points
ID: 22832789
Line 19 is ok, its just the indentation (too many spaces at the start of the line). It's not an error, it just "looks wrong".

EE does not have private messageing, as far as I know.

As for the blank screen... you should put in some error checking:
ini_set('display_errors', 1);

error_reporting(E_ALL);
 

if(isset($_POST['category'])) {

  $category = $_POST['category'];

  $sql = "SELECT * FROM ddcart_products 

          WHERE category = '".$category."' LIMIT ".$offset.", ".$numitems;    

  $result = mysql_query($sql) or die('Error: '.mysql_error());

  $i = 1;

  while($data = mysql_fetch_assoc($result)) {

    echo 

    '<div class="productblock draggablediv">'.

      '<div class="pbimage">'.

        '<img width=150 src="'.$data['photourl'].'" alt="" />'.

      '</div>'.

      '<div class="pbinfo"><a href="productdetail.php?product='.$data['id'].

        '" class="detailslink">View Details</a></div>'.

      '<div class="pbtitle">'.stripslashes($data['name']).'</div>'.

      '<div class="pbprice">$'.number_format($data['price'], 2, '.', ',').'</div>'.

    '</div>';

    if(($i % 4) == 0) 

      echo '<div class="clear"></div>';

    $i++;

  }

  echo '<div class="clear"></div><div id="pagenums" style="text-align: center;">';

  //total number of pages

  $sql = "SELECT count(*) FROM ddcart_products WHERE category = '".$category."'";

  $result = mysql_query($sql) or die('Error: '.mysql_error());

  $numpages = ceil(mysql_num_rows($result)/$numitems);

  for($i = 1; $i <= $numpages; $i++) {

    if($page == $i) {

      echo '<strong><span style="font-size: 12px; text-decoration: underline;">'.

           '<a href="index.php?category='.$category.'&amp;page='.$i.'">'.$i.'</a></strong>';

    } else {

      echo '<a href="index.php?category='.$category.'&amp;page='.$i.'">'.$i.'</a>';

    }

  }

  echo '</div>';

}

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Author Closing Comment

by:rlb1
ID: 31511019
Thanks for your help!!  I appreciate it.
0

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