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Extract javascript block from ajax content and execute it

Posted on 2008-10-28
6
2,603 Views
Last Modified: 2012-05-05
HI,

I would like to extract a specific javascript block, which has an ID, from the content I received by making an ajax call and then execute that javascript block. Is it possible to do it using JQuery? Here's how I started out:
$(document).ready(function(){

           

   $.ajax({

            url: "Page2.aspx",

            type: "GET",

            success: function(content){

                    

                var scriptBlock = $(content).find('script#myscript');

                

                // Now execute the script block

            }

          });

});

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Question by:wtor
  • 3
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6 Comments
 
LVL 9

Expert Comment

by:Shahzad Fateh Ali
ID: 22828857
What is in your response, a javascript code or html?
If it is only javascript then put your code in a function and then after ajax call you will be able to call that function.

see the example

/* response */

<script>

function fnOne(){

 alert("Function one called");

}

function fnTwo(){

 alert("Function two called");

}

</script>

/* end response */
 

/* after ajax call */
 

success: function(content){

                    

        eval(content);      // make the script executable

        fnTwo();            // call to the function

            

         // Now execute the script block

   }

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Author Comment

by:wtor
ID: 22828916
Sorry I forgot to mention that my response was the entire HTML of Page.aspx.
0
 
LVL 9

Expert Comment

by:Shahzad Fateh Ali
ID: 22828931
Can you place your response html here?
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Author Comment

by:wtor
ID: 22828945
Here's the HTML:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 

<html xmlns="http://www.w3.org/1999/xhtml">

<head runat="server">

    <title>Untitled Page</title>

</head>

<body>

    <form id="form1" action="Page.aspx">
 

        <script id="myscript" type="text/javascript">

            

            function demoClass()

            {

                var myval;

            }

            

            var obj = new demoClass();

            obj.myval = 10;

            

            alert( "This is a script in page 2. Value: " + obj.myval );

        </script>
 

    </form>

</body>

</html>

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LVL 16

Accepted Solution

by:
sh0e earned 250 total points
ID: 22828964

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>

<script>

$(document).ready(function(){

   $.ajax({

            url: "Page2.aspx",

            type: "GET",

            cache: false,

            dataType: 'xml',

            success: function(xml){

                    

                eval($('script#myscript',xml).text())

            }

          });

});

</script>

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Author Comment

by:wtor
ID: 22829168
Thanks sh0e for pointing me to the right direction. I just had to change the dataType to html and it worked!
I dont like using eval. If you google, you'll know why. Here's the final code:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>

<script>

$(document).ready(function(){

   $.ajax({

            url: "Page2.aspx",

            type: "GET",

            cache: false,

            dataType: 'html',

            success: function(html){

                    

            var myScript = new Function($('script#myscript',html).text());
 

myScript();

            }

          });

});

</script>

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