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VB 2005 Combobox TextChanged Event. Distinguish between programmatic modification or user interaction.

I'm populating a combobox in vb 2005 like this.  This line in the code is calling the TextChanged event.
cmbfiletypecode.Text = dr("filetypecode").ToString.Trim

When a user changes one of the values in the combo box it calls the same event.  How can I isolate whether the user has changed a value or it's been changed programatically?



        dt4.Clear()
        cCmd.CommandText = "Select distinct FileTypecode from FileType where FileTypecode is not null order by FileTypecode"
        adapter.SelectCommand = cCmd
        adapter.Fill(dt4)
        cmbFileTypeCode.DisplayMember = "FileTypecode"
        cmbFileTypeCode.ValueMember = "FileTypecode"
        cmbFileTypeCode.DataSource = dt4
        dt4a.Clear()
        cCmd.CommandText = "Select FileNamecode,filetypecode from FileCoverage where FileNamecode = '" & FileNameCode & "'"
        adapter.Fill(dt4a)
        If dt4a.Rows.Count > 0 Then
            For Each dr In dt4a.Rows
                If dr("FileNamecode") = FileNameCode Then
                    cmbfiletypecode.Text = dr("filetypecode").ToString.Trim
                End If
            Next
        Else
            'cmbFileTypeCode.Text = ""
            cmbFileTypeCode.Text = Form1.Grid1(5, i).Value
        End If
0
AlHal2
Asked:
AlHal2
1 Solution
 
Mike TomlinsonMiddle School Assistant TeacherCommented:
One solution would be to use a flag which you can check in the TextChanged() Event:

Public Class Form1
 
    Private MyChange As Boolean = False
 
    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        MyChange = True
        cmbfiletypecode.Text = "something"
    End Sub
 
    Private Sub cmbfiletypecode_TextChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles cmbfiletypecode.TextChanged
        If Not MyChange Then
            MessageBox.Show("TextChanged")
        Else
            MyChange = False
        End If
    End Sub
 
End Class

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AlHal2Author Commented:
Thanks.
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