How do you create a menu that uses an array of function pointers?
I'm trying to create a program with a menu that uses an array of function pointers. So when the user selects an option the appropriate function is called. I know that I am close to figuring this out, but just haven't quite got it. (I know that I could use a switch statement but I'm suposed to use this array.) Please tell me what's wrong with my code. Also is there another way that I can initialize each element in my char array to "none"?
const int size = 10;
const int length = 25;
char Name[size][length] = {"none","none","none","none","none","none","none","none","none","none"};
int main()
{
int Option = 0;
int (*fptr[6])(char[size][length]) = {Add, Update, Delete, Sort, Print, Quit};//declaration creating array of fuction pointers
do
{
system("cls");
cout << "Main Menu",
cout << "\n",
cout << "1) Add\n",
cout << "2) Update\n",
cout << "3) Delete\n",
cout << "4) Sort\n",
cout << "5) Print\n",
cout << "6) Quit\n" << endl;
cout << "Enter Selection" << endl;
cin >> Option;
if(Option < 1 || Option > 6)
{
cout << "invalid entry - please re-enter" << endl;
} else
{
cout << fptr[Option - 1]() << endl;
}
}while(Option != 6);
return 0;
}
Hi b_acs,
I think you need to write '(*fptr[Option - 1])()' to call the functions via their pointer.
Hope that helps,
ZOPPO
I think you need to write '(*fptr[Option - 1])()' to call the functions via their pointer.
Hope that helps,
ZOPPO
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>> Why you are doing in the hard way and not just use Switch statement?
Using function pointers for this kind of stuff is cleaner. You don't need a switch.
Using function pointers for this kind of stuff is cleaner. You don't need a switch.
ASKER
I knew I was close! Thank you!
Btw, instead of having something like this :
int (*fptr[6])(char[size][leng
do yourself a favor, and make your life a little easier by using typedef's :
typedef int (*MenuFunction)(char[size]
This typedef is the function pointer as you defined it. You can then simply create an array of function pointers like this :
MenuFunction fptr[6] = { ... };
Much easier to read and understand ;)
int (*fptr[6])(char[size][leng
do yourself a favor, and make your life a little easier by using typedef's :
typedef int (*MenuFunction)(char[size]
This typedef is the function pointer as you defined it. You can then simply create an array of function pointers like this :
MenuFunction fptr[6] = { ... };
Much easier to read and understand ;)
Regarding the initialization of your array why not use a nested for loop