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Conditional Sums within SQL

Posted on 2008-10-31
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I am attempting to calculate overtime hours worked from a query that obtains hours worked over a given time period.  The issue I'm having is that the query pulls back multiple associates for each date in the given date range and groups by 8 of the 9 columns in the data set.  So I'm at a loss at trying to determine how I can calculate each associate's overtime (if they worked any).

I am attaching the code I'm using as of now to pull back the hours worked.
``````SELECT	a.timeclock_date,

a.employee_id,

b.payroll_id,

CASE WHEN a.work_code = 1 THEN 'WORKED HOURS'

WHEN a.work_code = 10 THEN 'VACATION'

WHEN a.work_code = 11 THEN 'FUNERAL'

WHEN a.work_code = 15 THEN 'SICK'

WHEN a.work_code = 16 THEN 'PERSONAL' ELSE a.work_code END   as work_code ,

b.location_nmbr,

b.lname,

b.fname,

c.department_ID,

SUM(total_hours) AS total_hours

FROM 	edw1.timeclock a,

edw1.employee b,

(SELECT a.employee_ID AS payroll_id,

a.department_ID,

a.JOB,

MAX(a.work_dt) AS work_dt

FROM   edw1.payroll_job a,

(SELECT employee_ID AS payroll_id,

MAX(work_dt) AS work_dt

FROM   edw1.payroll_job

WHERE LOCATION = 01002

GROUP BY 1) b

WHERE 	a.LOCATION = 01002

AND      a.employee_ID = b.payroll_id

AND	a.action_dt= b.action_dt

GROUP BY 1,2,3) c

WHERE a.employee_id = b.employee_id

AND b.payroll_id= c.payroll_id

AND b.loc_num = 1002

AND a.timeclock_date BETWEEN '2008-10-01' AND '2008-10-29'

GROUP BY 1,2,3,4,5,6,7,8
``````
0
Question by:SpeedsterZ28
• 2

LVL 59

Expert Comment

ID: 22850301
Can you just make your original query derived and then do formulat outside.  For example if overtime is anything over 160 hours (40 hours x 4 work weeks):
``````SELECT *

, CAST(CASE WHEN total_hours > 160 THEN 1 ELSE 0 END AS BIT) AS WorkedOvertime

FROM (

SELECT	a.timeclock_date,

a.employee_id,

b.payroll_id,

CASE WHEN a.work_code = 1 THEN 'WORKED HOURS'

WHEN a.work_code = 10 THEN 'VACATION'

WHEN a.work_code = 11 THEN 'FUNERAL'

WHEN a.work_code = 15 THEN 'SICK'

WHEN a.work_code = 16 THEN 'PERSONAL' ELSE a.work_code END   as work_code ,

b.location_nmbr,

b.lname,

b.fname,

c.department_ID,

SUM(total_hours) AS total_hours

FROM 	edw1.timeclock a,

edw1.employee b,

(SELECT a.employee_ID AS payroll_id,

a.department_ID,

a.JOB,

MAX(a.work_dt) AS work_dt

FROM   edw1.payroll_job a,

(SELECT employee_ID AS payroll_id,

MAX(work_dt) AS work_dt

FROM   edw1.payroll_job

WHERE LOCATION = 01002

GROUP BY 1) b

WHERE 	a.LOCATION = 01002

AND      a.employee_ID = b.payroll_id

AND	a.action_dt= b.action_dt

GROUP BY 1,2,3) c

WHERE a.employee_id = b.employee_id

AND b.payroll_id= c.payroll_id

AND b.loc_num = 1002

AND a.timeclock_date BETWEEN '2008-10-01' AND '2008-10-29'

GROUP BY 1,2,3,4,5,6,7,8

) derived
``````
0

LVL 59

Accepted Solution

Kevin Cross earned 500 total points
ID: 22850358
If it needs to be determined based on aggregate date from some of the other records that are showing as independing rows because of the grouping and you are running SQL 2005 you can try summing in an OVER statement that only groups by employeeID.

SUM(total_hours) OVER (PARTITION BY a.employeeID ORDER BY a.timeclock_date) AS total_emp_hours

You can then analyze that in outer query or try putting that in CASE statement -- don't have SQL Manager to try at the moment.

CASE WHEN (SUM(total_hours) OVER (PARTITION BY a.employeeID ORDER BY a.timeclock_date)) > 160 THEN 1 ELSE 0 END AS WorkedOvertime
0

Author Closing Comment

ID: 31512041
Thank you very much!  Just what I needed!
0

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