URL decode in Oracle

What's the best way to decode URL characters when pulling data from Oracle?
stang1Asked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

ajexpertCommented:
Can u give example like what is the input (URL) and which way you want to represent?
0
stang1Author Commented:
the fields is varchar2(4000) and contains: (for example)
'Feb.+20%2C+2008%2C+Director+%28'
and my desired result:
'Feb. 20, 2008, Director ('
I'm just spooling to a .txt file and want to convert the encoded chars....
Thanks for your help....
0
stang1Author Commented:
the field is varchar2(4000) and contains: (for example)
'Feb.+20%2C+2008%2C+Director+%28'
and my desired result:
'Feb. 20, 2008, Director ('
I'm just doing a select and 3 tbls and spooling to a .txt file and want to convert the encoded chars....
Thanks for your help....
0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

ajexpertCommented:
Hi,
To my knowledge, oracle does not provide any functions for decoding URL.

However, you can use perl or java script for the same and call from oracle.

Hope it helps
0
MarkusIdCommented:
I'm afraid, not in version 9, but in version 11 (just in case anybody else is looking for somethink like this):

http://www.psoug.org/reference/utl_url.html
0
DiscoNovaCommented:
To my knowledge, the UTL_URL -package exists in Oracle 9 Release 2, however I'm not entirely certain of Release 1.
0
DiscoNovaCommented:
And, according to the page linked by MarkusId, it has indeed been first available in version 9.0.1.

So, to answer the original question, the solution to the example you gave (of course, you need to have execute privilege to the package SYS.UTL_URL, but I believe that has been granted to PUBLIC, so you propably don't need to worry about that) is:
SELECT UTL_URL.UNESCAPE('Feb.+20%2C+2008%2C+Director+%28') FROM DUAL;

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
stang1Author Commented:
I just added a replace for the '+' and it worked really well.  Thanks!
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Oracle Database

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.