Parse error: parse error, expecting `T_OLD_FUNCTION' or `T_FUNCTION' or `T_VAR' or `'}''

What am I doing wrong?

I am making a class for connecting to a MySql database, but when testing it, it brings back a blank page. Debugging in eclipse reveals Parse error: parse error, expecting `T_OLD_FUNCTION' or `T_FUNCTION' or `T_VAR' or `'}'' in c:\program files\easyphp1-8\www\lib\framework\system.data.mysqlclient.php on line 27

/**
 * Defines a connection to the database
 *
 */
class MySqlConnection
{
	var $Connection = 0;
	var $server;
	var $username;
	var $password;
	var $database;
	/**
	 * Initializes connection to a MySQL Server
	 *
	 * @param string $Server
	 * @param string $Username
	 * @param string $Password
	 * @param string $Database
	 */
	function __construct($Server, $Username, $Password, $Database)
	{
		$res = mysql_connect($Server, $Username, $Password);
		if(!$res) throw new Exception(MySqlConnectionException);
		if(!mysql_select_db($Database, $res)) throw new Exception(MySqlDatabaseOperationException);
		$Connection = $res;
	}
	/**
	 * Returns last occured error
	 *
	 * @return string
	 */
	function GetLastError()
	{
		return mysql_error();
	}
	
	/**
	 * Closes the database connection
	 *
	 */
	function Close()
	{
		mysql_close($Connection);
	}
}

Open in new window

LVL 1
webfullcircleAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

nahimeCommented:
On my test machine your code works (adding <?php at the start and ?> at the end).
I've tried to instantiate the class as in the code snippet
<?php
/**
 * Defines a connection to the database
 *
 */
class MySqlConnection
{
        var $Connection = 0;
        var $server;
        var $username;
        var $password;
        var $database;
        /**
         * Initializes connection to a MySQL Server
         *
         * @param string $Server
         * @param string $Username
         * @param string $Password
         * @param string $Database
         */
        function __construct($Server, $Username, $Password, $Database)
        {
                $res = mysql_connect($Server, $Username, $Password);
                if(!$res) throw new Exception(MySqlConnectionException);
                if(!mysql_select_db($Database, $res)) throw new Exception(MySqlDatabaseOperationException);
                $Connection = $res;
        }
        /**
         * Returns last occured error
         *
         * @return string
         */
        function GetLastError()
        {
                return mysql_error();
        }
        
        /**
         * Closes the database connection
         *
         */
        function Close()
        {
                mysql_close($Connection);
        }
}
 
$myvar = new MySqlConnection("127.0.0.1", "username", "password", "DATABASE");
?>

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
webfullcircleAuthor Commented:
That's odd.. I was using the require_once call and it did not work, but worked with include
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
PHP

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.