clintonJ
asked on
Opening Adobe Acrobat 8.0 from VB code
I have a VB 6.0 app. I can successfully open Adobe Acrobat 7.0 from my VB code, with the following line:
pat1 = "C:\Program Files\Adobe\Acrobat 7.0\Reader\AcroRd32.exe " ', vbNormalFocus '
pat2 = FolderFile
pa = pat1 & pat2
Shell pa, vbMaximizedFocus
However, I cannot open Adobe Acrobat 8.0 from VB code, even though I am using the same line:
pat1 = "C:\Program Files\Adobe\Reader 8.0\Reader\AcroRd32.exe " ', vbNormalFocus '
pat2 = FolderFile
pa = pat1 & pat2
Shell pa, vbMaximizedFocus
Thanks ahead of time.
pat1 = "C:\Program Files\Adobe\Acrobat 7.0\Reader\AcroRd32.exe " ', vbNormalFocus '
pat2 = FolderFile
pa = pat1 & pat2
Shell pa, vbMaximizedFocus
However, I cannot open Adobe Acrobat 8.0 from VB code, even though I am using the same line:
pat1 = "C:\Program Files\Adobe\Reader 8.0\Reader\AcroRd32.exe " ', vbNormalFocus '
pat2 = FolderFile
pa = pat1 & pat2
Shell pa, vbMaximizedFocus
Thanks ahead of time.
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
pat1 = "C:\Program Files\Adobe\Reader 8.0\Reader\AcroRd32.exe " ', vbNormalFocus '
pat2 = FolderFile
pa = pat1 & pat2
Shell pat1, vbMaximizedFocus ' change this line
what is the value of pa?