Hexadecimal addtion

Hi, this is a hexadecimal addtion.

Hex:

   3 A E
+ 1 F 5
  --------
   5 A 3


looking at the addtion above, if you add E and 5 why does the number become 13?

I thought , E = 14 thus it should be 14+5 = 19.

but I guess I'm wrong. can you please explain.
bt1942Asked:
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JohnBusiness Consultant (Owner)Commented:
Well,  14+5 decimal = 19 decimal = 3 Hex and carry the one (i.e. 13 Hex). Go from there. ... T
hongjunCommented:
Stage 1:

  3 A E
+ 1 F 5
  -----

Stage 2:

    1
  3 A E
+ 1 F 5
  -----
      3

Stage 3:

  1 1
  3 A E
+ 1 F 5
  -----
    A 3

Stage 4:

  1 1
  3 A E
+ 1 F 5
  -----
  5 A 3
bt1942Author Commented:
thinkpads_user// Hi, how did you get 13 hex?
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hongjunCommented:
Explanation to my above (Note all are in hexa):

Stage 1:

E + 5 = 13
So we carry "1" to the next stage

Stage 2:

1 + A + F = B + F = 1A
So we carry "1" to the next stage

Stage 3:

1 + 3 + 1 = 5


hongjun
JohnBusiness Consultant (Owner)Commented:
15 = F, 16 = 10H, 17 = 11H, 18 = 12H, 19 = 13H
.... T

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hongjunCommented:
Ya..

E + 5 = F + 4 = 10 + 3

So we carry 1 and then leave the 3 there.
PaulHewsCommented:
>looking at the addtion above, if you add E and 5 why does the number become 13?

Because hex 13 is dec 19

Where decimal values "roll over" to the next power at 10, hexadecimal rolls over at 16.

One in the 16s place and 3 in the 1s place.
WaterStreetCommented:
Here is a way to visualize it.

Hex-E-Plus-5.gif
bt1942Author Commented:
Thanks for your help.
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