asked on

SQL Problem

Hi Experts.

It's one of those days, I just cant get this to work as I want it to, can anyone help.

I have a table:
ID      ParentID      Title

1      NULL      Personal, social and emotional development
2      NULL      Communication, language and literacy
3      NULL      Problem solving, reasoning and numeracy
4      NULL      Knowledge and understanding of the world
5      NULL      Physical development
6      NULL      Creative development
7      1      Dispositions and attitudes
8      1      Social development
9      1      Emotional development
10      2      Language for communication and thinking
11      2      Linking sounds and letters
12      2      Reading
13      2      Writing
14      3      Numbers as labels and counting
15      3      Calculating
16      3      Shape, space and measure

I want to recreate the menu structure such that I return the title and next to it the relavent sub menus based on ID/Parent ID. This I can do. In addition if the parentID id null (its a top level) and it has no children then it's title appears in the same column as the sub menus. It can appear twice once in the main men and again in the sub ment columns, all I can get is it displays Null, which is it value.

Just to help there should be 6 different main menu headings, and 13 sub menus, 3 of which should be the same as the main menu.

Andy

Kevin Cross

Is this what you are looking to do?

SELECT m.ID, CASE WHEN p.Title IS NOT NULL THEN p.Title + ' - ' ELSE '' END + m.Title
FROM MenuTable m
LEFT JOIN MenuTable p ON p.ID  = m.ParentID

Open in new window

Andy Green

ASKER

Thanks, but not quite.
I dont need the concatenation, I need them in separate columns, there will be 13 in total with 3 rows, the id, the main menu and sub menu columns
I'll have a play with what you've given me so far.
Andy

varungd

Try this

SELECT parentId, Title from
 ( SELECT p1.ParentID,
          ( SELECT  Title + ','
              FROM TableName  p2
             WHERE p2.parentID = p1.ParentId
               FOR XML PATH('') ) AS Title
  FROM TableName  p1 
      GROUP BY ParentID
 
) A

Open in new window

Andy Green

ASKER

Sorry, I should have said 13 rows, 3 colums.
Andy

Kevin Cross

-- select sub menu items with parent information
SELECT m.ID AS MenuID
, p.Title AS MainMenu
, p.Title AS SubMenu
FROM MenuTable m
INNER JOIN MenuTable p ON p.ID = m.ParentID
UNION ALL -- can use UNION to filter out duplicates
-- join in parent menu with no children
SELECT ID AS MenuID
, Title AS MainMenu
, Title AS SubMenu
FROM MenuTable
WHERE ID NOT IN (SELECT ParentID FROM MenuTable)
AND ParentID IS NULL

Andy Green

ASKER

Still not right - it returns 3 column, but the menu and sub menu are the same.
this sql

SELECT a.AssessmentScale_ID, CASE WHEN b.AssessmentScale_Title IS NOT NULL THEN b.AssessmentScale_Title ELSE '' END , a.AssessmentScale_Title
FROM tbl_AssessmentScale a
LEFT JOIN tbl_AssessmentScale b ON b.AssessmentScale_ID = a.AssessmentScaleParent_ID

Returns this data
1 Personal, social and emotional development
2 Communication, language and literacy
3 Problem solving, reasoning and numeracy
4 Knowledge and understanding of the world
5 Physical development
6 Creative development
7 Personal, social and emotional development Dispositions and attitudes
8 Personal, social and emotional development Social development
9 Personal, social and emotional development Emotional development
10 Communication, language and literacy Language for communication and thinking
11 Communication, language and literacy Linking sounds and letters
12 Communication, language and literacy Reading
13 Communication, language and literacy Writing
14 Problem solving, reasoning and numeracy Numbers as labels and counting
15 Problem solving, reasoning and numeracy Calculating
16 Problem solving, reasoning and numeracy Shape, space and measure
This is what I want except - 1,2,& 3 have sub menus so I dont want to see them at the top, and 4, 5 & 6 dont have submenus so I want to see the text in the second colum as the menu title.
Andy

ASKER CERTIFIED SOLUTION

Kevin Cross

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

Andy Green

ASKER

Thank you, I unioned in the first 3 rows and it exactly what I wanted.

Andy