printig 20 lines from string

hi  I need to write an awk script that prints 20 lines from a string and directs output to a file.
pls help.
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Can you give an example of the input and desired output?
How does your string store 20 lines?
strings in shell scripts do not have \n or \r or anything like that in tham as far as I know.

If you have managed to get new lines into a string then you could echo it and then pipe it to head and then pipe that into a file

echo "$string" | head -n 20 > /path/file.txt

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The question needs clarification.  At this point all we could do is guess at the i/o.
assuming string (as asked for in the original question) is in file named string.txt:

head -20 string.txt>file
tail -20 string.txt>file
sed -ne '1,20p' string.txt>file
awk '(NR<21){print}' string.txt>file
awk 'END{printf"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n"}' string.txt>file

Note: only the last examples ensures that you realy get 20 lines.

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mbpssgmsAuthor Commented:
thanks I'd been away.  This was similar to another solution.
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Shell Scripting

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