How can I get the List Separator under Visual Basic .NET 2003?

Dears,

I would like to ask if you could advice how can I get the List Separator from Locale in VB 2003.
If I used the solution of VB 6 (GetLocalInfo()) it was not working.

Could you tell me what i did wrong?

Thank you so much
best regards
Public Declare Function GetLocaleInfo Lib "kernel32" Alias _
      "GetLocaleInfoA" (ByVal Locale As Long, ByVal LCType As Long, ByVal lpLCData As String, _
           ByVal cchData As Long) As Long
 
Public Const LOCALE_SLIST = &HC
 
Dim ListSeparator As String
GetLocaleInfo(Locale, LOCALE_SLIST, ListSeparator, 0)

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eesdilAsked:
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TimCotteeHead of Software ServicesCommented:
Hello eesdil,

Dim ListSeparator As String = System.Globalization.TextInfo.ListSeparator()

Regards,

TimCottee
0
eesdilAuthor Commented:
Hi Tim,

Thank you for the quick answer.
but I have some issues with it :)
Do I have to declare something for it?

I have tried usage from msdn, but it didnt work either...
It is throwing an excepten: Object reference not set to an instance of an object

Could you help what it is?
thanks in advance

regards,
csaba

Dim infoInstance As TextInfo
Dim listSep As String
 
listSep = infoInstance.ListSeparator

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TimCotteeHead of Software ServicesCommented:
eesdil,

As always it is never quite as easy as it should be:

TimCottee
        Dim instance As Globalization.CultureInfo = System.Threading.Thread.CurrentThread.CurrentCulture
        MsgBox(instance.TextInfo.ListSeparator)

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eesdilAuthor Commented:
Hi Tim,

thanks a lot it is working perfectly (out of box)

best regards,
csaba
0
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