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Java charAT Method

I working on this problem in Java. Got it to work one way and now I need to know how to do a charAt method.

Which I no nothing about.

When the User assigns a letterGrade string return a value but add 0.3 for + and -.03

Any guidance or help would greatly be appreciated.

package singlegradeprinter;
import java.util.Scanner;
public class SingleGradePrinter 
{  
    public static void main(String[] args) 
{
     Scanner in = new Scanner(System.in);
     
     System.out.println("Enter a letter grade:");
     String input = in.nextLine();
     
     Grade g = new Grade(input);
     
     double grade = g.getNumericGrade();
     System.out.println("Numeric value: " + grade);      
         }
}
***************************************
package singlegradeprinter;
public class Grade 
{
    public Grade(String initGrade)
    {
        letterGrade = initGrade;
    }
    public double getNumericGrade()
    {
          //double grade = 0;  
               
        //    if (letterGrade.equals("A+")){
          //          return (4.0);
          //  }else if (letterGrade.equals("A")){
            //        return (4.0);         
         //   }else if (letterGrade.equals("A-")){
           //         return (3.7);        
         //   }else if (letterGrade.equals("B")){
           //         return (3.0);
           // }else if (letterGrade.equals("C")){
             //        return (2.0);
            //}else if (letterGrade.equals("D")){
              //       return (1.0);
          //  }else if (letterGrade.equals("F")){
           // }     return (0.0);            
                
double grade;
for( int i=0; i > letterGrade.length(); i++){
    // System.out.println("char = " + igrade.charAt(i));
    if(i = (+) )
        grade = grade + 0.3;
    else if (i = (-))
            grade = grade - 0.3;
}
        }
         
    private String letterGrade;
    
}

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SOLUTION

aaronblum

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Kevin Cross

And you usually have to make the comparison like this using == as = will assign a value instead of test it for equality.

if ("A+".charAt(1) == '+') {
// ...
}

So in your case:
igrade.charAt(i)

One difficulty with this that you are overcoming by using a loop is that the index 1 may not be valid for the letter grades. Another means to this would be:

if ("A+".endsWith("+")) {
// ...
}

ASKER CERTIFIED SOLUTION

Kevin Cross

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ca1358

ASKER

Thank you both!