Need function to convert from yyyymm to smalldatetime

hi
I have a Calendar table that lists yyyyww (IntelYearWW) values (eg; 200847) and dates for those weeks (IntelDate) (eg: for 200847 the dates would range from the Sunday 16 Nov to the Saturday 22/Nov)
I need a function that will  take yyyyww as an input value, and output the first date (min(IntelDate) for that week
thanks
Fergal
fjkilkenAsked:
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fjkilkenConnect With a Mentor Author Commented:
derived solution from another function
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BinuthCommented:
try this
declare @currentweek int
set @currentweek = 200847
declare @firstDayYear as datetime
set @firstDayYear = CAST('01/01/' + LEFT(@currentweek,4) AS DATETIME)
set @currentweek = RIGHT(@currentweek,2)
select dateadd(d,(((7*@currentweek)-datepart(dw,@firstDayYear))-6),@firstDayYear) as FirstDate

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fjkilkenAuthor Commented:
Hi
thanks but I need a function that directly references my Calendar table
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BinuthCommented:

CREATE FUNCTION GetMinWeekDate
(  @currentweek int)
RETURNS DATETIME
AS
BEGIN
 
 
	declare @firstDayYear as datetime
	set @firstDayYear = CAST('01/01/' + LEFT(@currentweek,4) AS DATETIME)
	set @currentweek = RIGHT(@currentweek,2)
 
	declare @FirstWeekDate as datetime
	select @FirstWeekDate = dateadd(d,(((7*@currentweek)-datepart(dw,@firstDayYear))-6),@firstDayYear)  
 
	declare @LastWeekDate as datetime
	select @LastWeekDate=dateadd(d,((7*@currentweek)-datepart(dw,@firstDayYear)),@firstDayYear) 
 
 
	return (select MIN(IntelDate) from TableName where IntelDate between @FirstWeekDate and @LastWeekDate)
 
END

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fjkilkenAuthor Commented:
thanks but I got it figured out:



ALTER FUNCTION dbo.fn_yyyyww_to_date
(
      -- Add the input parameters for the function here
      @IntelWW as int
)
RETURNS TABLE
AS
RETURN
      (
            select distinct IntelYearWW, min(IntelDate) as first_day_IntelWW
            from dbo.Calendar where IntelYearWW = @IntelWW group by IntelYearWW
      )
0
 
fjkilkenAuthor Commented:
derived solution from another function
0
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