subtract current time to end of day - php

How do I subtract the current time till the end of the day in PHP?

2:33:27 - 12:00:00 (midnight)

I want a result of 9 hours 27 minutes and 33 seconds
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bschwartingAsked:
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Beverley PortlockCommented:
This will do it as spec'd

<?php

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - time();

echo date("H \h\o\u\\r\s i \m\i\\n\u\\t\e\s s \s\e\c\o\\n\d\s",$timeLeft);
?>

The escaping is to stop the date function interpreting the text as directives.
Beverley PortlockCommented:
If you want to split out the hours etc then alter the above like so

<?php

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - time();

$hours = date("H",$timeLeft);
$mins  = date("i",$timeLeft);
$secs  = date("s",$timeLeft);

echo "Time left is $hours hours, $mins minutes and $secs seconds";
?>
bschwartingAuthor Commented:
the 1st option gives me 4 hours instead of 9.
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Beverley PortlockCommented:
Well, it would do - there is only 4 hours (or so) to midnight - in this timezone.....
Roger BaklundCommented:
Try this:
$one_day = 60*60*24;
$rest_of_day = $one_day - (time() + date('Z')) % $one_day;
echo gmdate('G \h\o\u\r\s i \m\i\n\u\t\e\s \a\n\d s \s\e\c\o\n\d\s',$rest_of_day);

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bschwartingAuthor Commented:
perfect, thanks!
Beverley PortlockCommented:
OK here it is modified to use your example time (which gives 9 hours to go)

<?php
$sampleTime = strtotime("14:33:27");

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - $sampleTime;

$hours = date("H",$timeLeft);
$mins  = date("i",$timeLeft);
$secs  = date("s",$timeLeft);

echo "Time left is $hours hours, $mins minutes and $secs seconds";
?>
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