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Could you try the following sample. I'vemade a change to the last line and the $sql line. 

<pre><code class="code-10 nolinks" id="code-233067">function myFunction()
{
 $tablename = &quot;login&quot;;
 $sql = &quot;SELECT * FROM $tablename WHERE username = '&quot; . $_POST[&quot;username&quot;] . &quot;'&quot;;
 $result = @mysql_query($sql, $connection) or die(mysql_error());
 $num = mysql_num_rows($result);
 
 if ($num != 0) 
 {
 echo &quot;&lt;h5&gt;Logged in Username has Already been taken&lt;/h5&gt;&quot;;
 } 
}
 
myFunction();
</code></pre>
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<div>
I tried that already with the brackets, I removed them before because I thought maybe it would work.
</div>

<div>
Have you tried the change to the line starting with $sql = ? That line also contained a problem. 
 
What you should probably also try is adding the following like after the line with mysql_query: 
 
echo mysql_error(); 
 
This may return an error from your sql query.
</div>

<div>
That alll works outside of a function, no problems with that.
</div>

<div>
Yes, that's it. Stupid I didn't see it :).
</div>

<div>
<div class="content wysiwyg-content">
My code works outside of a function, but when using a function it doesnt work. I even tried a suggested solution of writing return null at the end of the function but it did not work, can you please assist me. 

<pre><code class="code-10 nolinks" id="code-233064">function myFunction()
{
$tablename = &quot;login&quot;;
$sql = &quot;SELECT * FROM $tablename WHERE username = '$_POST[username]'&quot;;
$result = @mysql_query($sql, $connection) or die(mysql_error());
$num = mysql_num_rows($result);
 
 
 
if ($num != 0) 
 
{
 
 
 
echo &quot;&lt;h5&gt;Logged in Username has Already been taken&lt;/h5&gt;&quot;;
 
 
} 
 
 
 
}
 
myFunction;
</code></pre>
</div>
</div>

My code works outside of a function, but when using a function it doesnt work. I even tried a suggested solution of writing return null at the end of the function but it did not work, can you please assist me.

PHP Function not Working

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