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saharey asked on

Find Replace with perl -pi

I am doing find and replace like this

find /path/to/folder -name '*.*' -print0 | xargs -0 perl -pi -e "s/3\.1\.00/8\.4\.0\.${DATE}/g"

When I run the above script it works fine, but the problem is it is replacing a text "3.1.00.00" also, I am confused how come it is replacing a 4 octet string.

I am not finding a string with 4 digits only 3 digits is being asked to replace.

Say string is "3.1.00.00" than it gets replaced like this "3.1.0.2009012800.00"

Anyone with a quick help?
Perl

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Last Comment
ozo

8/22/2022 - Mon
ozo

Do you only want to replace 3\.1\.00 only when it is not followed by \. ?
if so, you can do
s/3\.1\.00(?!\.)/8\.4\.0\.${DATE}/g
ASKER
saharey

it worked but the orginal string
"3.1.00" is now getting replaced like this "3..^@.2009012802"

ASKER CERTIFIED SOLUTION
ozo

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