substring for char*

   char s[] = "please help me";
    char s2[5];
    ZeroMemory(s2, 5);
    _tcsncpy(s2, &s[7], 4);


s2 now contains "help"

Or did you want strstr -
Returns a pointer to the first occurrence of a search string in a string.

copied from help files:

// crt_strstr.c

#include <string.h>
#include <stdio.h>

char str[] =    "lazy";
char string[] = "The quick brown dog jumps over the lazy fox";
char fmt1[] =   "         1         2         3         4         5";
char fmt2[] =   "12345678901234567890123456789012345678901234567890";

int main( void )
{
   char *pdest;
   int  result;
   printf( "String to be searched:\n   %s\n", string );
   printf( "   %s\n   %s\n\n", fmt1, fmt2 );
   pdest = strstr( string, str );
   result = (int)(pdest - string + 1);
   if ( pdest != NULL )
      printf( "%s found at position %d\n", str, result );
   else
      printf( "%s not found\n", str );
}

Hi Andy

I have tried your first solution

I am getting an error

C2664: 'wcsncpy' : cannot convert parameter 1 from 'char [5]' to 'wchar_t *'      c:\Documents and

Those functions are for char (as you asked for) not for wchar.
Try replacing char with TCHAR in the example I gave (that reverts to char for ASCII and wchar for UNICODE)

Alternatively, if you are working with char strings in a UNICODE app then replace _tcsncpy with strncpy.

Hi Andy

I have tried this code what you gave me in your first post

char s[] = "please help me";
char s2[5];
ZeroMemory(s2, 5);
_tcsncpy(s2, &s[7], 4);

I haven't try anything different

Regards
Karan