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XDim = 1792
yDim = 1394
mLat = 36.046375149261479
mLon = -95.965082645416274
lat1 = 36.013282878519043
Lon1 = -95.999565124511719
lat2 = 36.108062797830584
Lon2 = -95.845670700073242
x = (mLat - lat1) / (lat2 - lat1) * XDim
y = (mLon - Lon1) / (Lon2 - Lon1) * yDim
lblLat.Text = x
lblLon.Text = y
Dim lat1 As Double, lat2 As Double, Lon1 As Double, _
Lon2 As Double, x As Double, y As Double, mLat As Double, _
mLon As Double, XDim As Integer, yDim As Integer
XDim = 640
yDim = 425
mLat = 36.046323101022757
mLon = -95.965061187744155
lat1 = 36.031470597983571
Lon1 = -95.97630500793457
lat2 = 36.060964648518294
Lon2 = -95.921287536621108
x = (mLat - lat1) / (lat2 - lat1) * XDim
y = (mLon - Lon1) / (Lon2 - Lon1) * yDim
lblLat.Text = x
lblLon.Text = y
Dim XDim As Integer, yDim As Integer, delX As Decimal, _
tlLon As Double, brLon As Double, delY As Decimal, _
tlLat As Double, brLat As Double
Dim myLattitude As Double, myLon As Double
XDim = 640
yDim = 425
tlLon = -95.97630500793457
brLon = -95.921287536621108
tlLat = 36.060964648518294
brLat = 36.031470597983571
delX = (tlLon - (brLon)) / XDim
' delX = -0.0000859647989272849 but yours is 0.000085964798927284375
' mine ends with 849 yours 84375 min has a negative yous don't if that matters
txtLon.Text = delX
delY = (tlLat - brLat) / yDim
' delY = 0.0000693977659640536 NOT 0.000069397766 its like yours rounded
txtLat.Text = delY
Dim y As Integer = 212
myLattitude = tlLat - y * delY
Dim X As Integer = 132
myLon = tlLon + X * delX
txt1.Text = myLattitude
txt2.Text = myLon
http:/Q_22013975.html#17669496
What it appears to me Arthur is doing is representing your location as a fraction of the x and y coordinates of the UI. In the linked additional comment, you will see that the next step is to multiply the fraction by the total number of pixels for x and y. In your case they are both 800.
So for example, you have this:
X = (Lat - Lat1) / (Lat2 - Lat1) * 800 ==> your x positioning on the bitmap
Y = (Long - Long1) / (Long2 - Long1) * 800 ==> your y positioning on the bitmap