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how do the com.springmvc.action.springservlet to be Spring controller?

Posted on 2009-02-12
Medium Priority
Last Modified: 2013-11-11
How to do this in my spring-servlet.xml file
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd" >
<bean name="/submitResult.htm" class="com.springmvc.action.springservlet">
<bean id="viewResolver" class= "org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="suffix">

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Question by:czutshi
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LVL 92

Accepted Solution

objects earned 2000 total points
ID: 23620400
Its your code that needs to change. subclassing AbstractController is the go if its relatively soimple.

LVL 92

Assisted Solution

objects earned 2000 total points
ID: 23620401

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