how do the com.springmvc.action.springservlet to be Spring controller?

Posted on 2009-02-12
Last Modified: 2013-11-11
How to do this in my spring-servlet.xml file
<?xml version="1.0" encoding="UTF-8" ?>



<bean name="/submitResult.htm" class="com.springmvc.action.springservlet">


<bean id="viewResolver" class= "org.springframework.web.servlet.view.InternalResourceViewResolver">

<property name="suffix">





Open in new window

Question by:czutshi
    LVL 92

    Accepted Solution

    Its your code that needs to change. subclassing AbstractController is the go if its relatively soimple.
    LVL 92

    Assisted Solution


    Featured Post

    IT, Stop Being Called Into Every Meeting

    Highfive is so simple that setting up every meeting room takes just minutes and every employee will be able to start or join a call from any room with ease. Never be called into a meeting just to get it started again. This is how video conferencing should work!

    Join & Write a Comment

    Suggested Solutions

    Introduction This article is the second of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers the basic installation and configuration of the test automation tools used by…
    International Data Corporation (IDC) prognosticates that before the current the year gets over disbursing on IT framework products to be sent in cloud environs will be $37.1B.
    The viewer will learn how to implement Singleton Design Pattern in Java.
    This tutorial covers a practical example of lazy loading technique and early loading technique in a Singleton Design Pattern.

    755 members asked questions and received personalized solutions in the past 7 days.

    Join the community of 500,000 technology professionals and ask your questions.

    Join & Ask a Question

    Need Help in Real-Time?

    Connect with top rated Experts

    24 Experts available now in Live!

    Get 1:1 Help Now