Sorry, the random variable is Y, not X. I'm guessing you already picked up on that :)

Solved

Posted on 2009-02-15

Please prove that

V(Y) = E[Y*Y] - (E[Y]*E[Y]),

where V is the Variance and E is the Expected value of a random variable X

V(Y) = E[Y*Y] - (E[Y]*E[Y]),

where V is the Variance and E is the Expected value of a random variable X

5 Comments

I thin the rest of that assignment should become clear then

I have this result

V(Y)=E(Y^2)-E(2YE(Y))+E(Y)

Is it correct so far? If Yes, then can I continue like this?

V(Y)=E(Y^2)-2E(YE(Y))+E(Y)

V(Y)=E(Y^2)-2E(Y)E(Y)+E(Y)

Please excuse any idiotic statements, I am a beginner in probability theory, at the very most!

By clicking you are agreeing to Experts Exchange's Terms of Use.

Title | # Comments | Views | Activity |
---|---|---|---|

File Server Growth. | 9 | 45 | |

Locating peaks of a graph in Excel | 9 | 45 | |

CAGR Calculation For SIP | 13 | 55 | |

Frequency distribution | 6 | 35 |

Join the community of 500,000 technology professionals and ask your questions.

Connect with top rated Experts

**14** Experts available now in Live!