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Delete old files based on date ?

I have files that I need to get rid of ...
But I would like to delete the files before a certain date (created).
can I specify a range ?
let's say delete files between 10Jan and 14Jan
thanks.

Aard Vark

Definitely want to delete files created before a certain date, or modified before a certain date? For example, a text file created on the 01/01/2009 could have been modified on 02/02/2009, but still created at the older date. If you want to get rid of files which aren't being modified for a certain amount of time (using batch), try using the ForFiles command (http://www.ss64.com/nt/forfiles.html). I'm not sure if there's any easy way to delete files created before a certain date in a batch file (VBS or Powershell could do this easily).

Might also be worth looking at https://www.experts-exchange.com/questions/20947290/Delete-All-Contents-of-Folder-Older-than-7-Days.html.

SET DIRECTORY=c:\temp
:: To test use ForFiles /p %DIRECTORY% /S /M *.* -d -16/09/2008 -c "cmd /c @echo @path"
ForFiles /p %DIRECTORY% /S /M *.* -d -16/09/2008 -c "cmd /c @del /q @path"

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t0t0

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t0t0

By the way, you can also call the batch file from within another batch file. But remember to pass it both dates as before ie,

:
CALL delrange 26/01/2008 28/02/2009
:

NOTE: I've condensed the last line.... otherwise it's the same as the code above.

@echo off
setlocal enabledelayedexpansion
set d1=%1
set d2=%2
set d1=!d1:~6,4!!d1:~3,2!!d1:~0,2!
set d2=!d2:~6,4!!d2:~3,2!!d2:~0,2!

for %%a in (*.*) do (
set fn=%%a
set fd=%%~ta
set fd=!fd:~6,4!!fd:~3,2!!fd:~0,2!
if !fd! GEQ !d1! if !fd! LEQ !d2! del !fn!
)