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How can I perform "Logical OR" in a regular expression in sed?
I would like to perform Logical OR operations in SED.
For instance, instead of s/[ab]/c/
I would like to do s/SentenceA|SentenceB/Sent
Is this possible?
For instance, instead of s/[ab]/c/
I would like to do s/SentenceA|SentenceB/Sent
Is this possible?
Shell Scripting
Last Comment
Maciej S
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Hello mate!
you can apply pattern multiple times. See if that sample can help:
you can apply pattern multiple times. See if that sample can help:
echo "cat dog fox" |sed -e 's/dog/cat/g' -e 's/fox/cat/g'
ASKER
Thank you, I did not realise this!!
I think it's not fair that my answer got accepted alone - the first answer is also correct, you should at least consider splitting the points.
In case author have GNU sed, then I have to admit, that your answer is much better. No need to remember what should be escaped. I agree with author about chosen answer :)
There may be only need to escape '|' character with backslash.
sed 's/SentenceA\|SentenceB/Se
If these sentences contains spaces:
sed 's/\(Sentence A\)\|\(Sentence B\)/Sentence C/'