Can someone check to see that I have obtained the correct figures as follows;

http://www.experts-exchange.com/Other/Math_Science/Q_24256263.html

Following on from the above, can someone check to ensure that I have correct figures and that I am doing this right because the figures are coming up incorrect when I run them through a java multilateration program that I got of the paper below (pdf attached). (I converted to java to work with my software)

The figures I get are

x=0

ti=19.0

tk=24.0

tj=24.0

tl=28.0

x=0
y=-49
z=0
 
package DataCalculations;
 
import java.lang.Math;
 
public class Multilateration {
 
     public double calcCord(int rNum, char cord) {
          
 
            OrgData og = new OrgData();
 
            double ti = og.getValue(rNum), tk = og.getValue(rNum + 1), tj = og
                        .getValue(rNum + 2), tl = og.getValue(rNum + 3);           // invoke toa figures from database
            
            System.out.println("\nti="+ti);
            System.out.println("\ntk="+tk);
            System.out.println("\ntj="+tj);
            System.out.println("\ntl="+tl);
            double xi = 1, xk = 0, xj = 10, xl =0;
            double yi = 1, yk = 1, yj = 0, yl = 0;
            double zi = 0, zk = 0, zj = 0, zl = 0;
 
            double xji = xj - xi;
            double xki = xk - xi;
            double xjk = xj - xk;
            double xlk = xl - xk;
            double xik = xi = xk;
            double yji = yj - yi;
            double yki = yk - yi;
            double yjk = yj - yk;
            double ylk = yl - yk;
            double yik = yi - yk;
            double zji = zj - zi;
            double zki = zk - zi;
            double zik = zi - zk;
            double zjk = zj - zk;
            double zlk = zl - zk;
 
            double rij = Math.abs((10*(ti - tj))/33);
            double rik = Math.abs((10*(ti - tk))/33);
            double rkj = Math.abs((10*(tk - tj))/33);
            double rkl = Math.abs((10*(tk - tl))/33);
 
            double s9 = rik * xji - rij * xki;
            double s10 = rij * yki - rik * yji;
            double s11 = rik * zji - rij * zki;
            double s12 = (rik
                        * (rij * rij + xi * xi - xj * xj + yi * yi - yj * yj + zi * zi - zj
                                    * zj) - rij
                        * (rik * rik + xi * xi - xk * xk + yi * yi - yk * yk + zi * zi - zk
                                    * zk)) / 2;
 
            double s13 = rkl * xjk - rkj * xlk;
            double s14 = rkj * ylk - rkl * yjk;
            double s15 = rkl * zjk - rkj * zlk;
            double s16 = (rkl
                        * (rkj * rkj + xk * xk - xj * xj + yk * yk + zk * zk - zj * zj) - rkj
                        * (rkl * rkl + xk * xk - xl * xl + yk * yk - yl * yl + zk * zk - zl
                                    * zl)) / 2;
 
            double a = s9 / s10;
            double b = s11 / s10;
            double c = s12 / s10;
            double d = s13 / s14;
            double e = s15 / s14;
            double f = s16 / s14;
            double g = (e - b) / (a - d);
            double h = (f - c) / (a - d);
            double i = (a * g) + b;
            double j = (a * h) + c;
            double k = rik * rik + xi * xi - xk * xk + yi * yi - yk * yk + zi - zk
                        * zk + 2 * j * yki;
            double l = 2 * (g * xki + i * yki + zki);
            double m = 4 * rik * rik * (g * g + i * i + l) - l * l;
            double n = 8 * rik * rik * (g * (xi - h) + i * (yi - j) + zi) + 2 * l
                        * k;
            double o = 4 * rik * rik
                        * ((xi - h) * (xi - h) + (yi - j) * (yi - j) + zi * zi) - k * k;
            double s28 = n / (2 * m);
            double s29 = (o / m);
            double s30 = (s28 * s28) - s29;
            double root = Math.sqrt(s30);
            
            if (cord == 'x'){
               int x;
                x = this.getX(g, zl, h);
                System.out.println("\nx="+x);
                return x;
            } 
            
              if (cord == 'y'){
                int y;
                y = this.getY(a, this.getX(g, zl, h), b, this.getZ(s28,root), c);
                System.out.println("\ny="+y);
                return y;
            }
            
            if (cord == 'z'){
                int z;
                z = this.getZ(s28,root);
                System.out.println("\nz="+z);
                return z;
            } 
            
            return -1;
 
      }      
 
      int getZ(double s28, double root) {
            int z1 = (int) (s28 + root);
            return z1;
      }
 
      // int z2=(int)(s28-root); // 
 
      int getX(double g, double z1, double h) {
            int x1 = (int) (g * z1 + h);
            return x1;
      }
 
      // int x2=(int)(g*z2+h); // 
      
      int getY(double a, double x1, double b, double z1, double c) {
            int y1 = (int) (a * x1 + b * z1 + c);
            return y1;
      }
      // int y2=(int)(a*x2+b*z2+c); 
      
     
 
}

Open in new window

A-Synthesizable-VHDL-Model-of-th.pdf
LVL 1
jtiernan2008Asked:
Who is Participating?

Improve company productivity with a Business Account.Sign Up

x
 
d-glitchConnect With a Mentor Commented:
In the screen shot, is see two RX4's and no RX2.  That doesn't seem correct.

What is the program supposed to do??

   Take in a set a DTOA data and generate a position estimate?
0
 
jtiernan2008Author Commented:
pic 2 attached below;
pic.png
0
 
d-glitchCommented:
The distances and time delays seem to be correct.

There is no particular reason to use integer arithmetic in Java.
There might me if you were using FPGA/CPLD to run the calculations.

I don't understand Java that well or what you are trying to do in the program.

You do have to work with differential times.  So you need to subtract 19 from all
of your values before passing on the position solver.
0
Build your data science skills into a career

Are you ready to take your data science career to the next step, or break into data science? With Springboard’s Data Science Career Track, you’ll master data science topics, have personalized career guidance, weekly calls with a data science expert, and a job guarantee.

 
jtiernan2008Author Commented:
The program comes from the tutorial below
It algorithm and equation derivation are at the start of the paper.
A-Synthesizable-VHDL-Model-of-th.pdf
0
 
d-glitchCommented:

Your drawing has X1, X2, X3, X4
And your program has i, j, k, l 
 
l (el) in indistinguishable from 1 (one) in this font.
 
And your values don't seem to match.
 
            double xi = 1, xk = 0, xj = 10, xl =0;
            double yi = 1, yk = 1, yj = 0, yl = 0;
            double zi = 0, zk = 0, zj = 0, zl = 0;
 
Shouldn't all the values be 0 or 10.  You have three 1's in there.

Open in new window

0
 
d-glitchCommented:
The order of the points may be scrambled as well.
I can't tell if that makes a difference.
0
 
jtiernan2008Author Commented:
I enter the database details from the drawings and calculations as per the screenshot and get results;


ti=19.0
tk=24.0
tj=24.0
tl=28.0

and x=0, y=0, z=0

This does not match so I check my co-ordinates

ti=19.0 so from my diagram this must be RX3
tk=24.0 so this must be eigther RX1 or RX4
tl=28.0 so this must be RX2

So this must be a problem with the coding? Did I do the above ok?

database.jpg
0
 
jtiernan2008Author Commented:
Sorry that is a typo in the database but it does not matter as the program does not check this...
RX4 in the second row should be RX2

The formula is explained in the attached tutorial pdf above. It takes in toa data and calculates the dtoas line 39-40..

I know it is using integers for the CPLD system but it should still work?

The maths is explained in the first part of the attached pdf... does it look ok for my system?
0
 
jtiernan2008Author Commented:
it must be a problem with the code.
thanks for checking the diagram and workings at least they are ok.
0
 
d-glitchCommented:
The mathematical approach described in the VHDL paper can work for your
application as well.

Note that they are not bothering to solve for or plot any of the hyperbolae.

Instead they are solving simultaneous equations for the position coordinates
(x, y, z) directly.

As you can see, the math is fairly tedious.
0
 
jtiernan2008Author Commented:
thanks that's the answer I was looking for
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.