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Mdx count measures

I want made a measures that count days between two dates, but the first date is same (2007-08-31), but the second is now or the fact's last date .

i have:
count([Time].[Date].&[2007-08-31T00:00:00]:[Time].[Date].&[2009-03-18T00:00:00])

i want :

count([Time].[Date].&[2007-08-31T00:00:00]: now) - [b]error[/b]

count([Time].[Date].&[2007-08-31T00:00:00]: Tail(NonEmpty([Time].[Year - Month - Date].Members,[Measures].[qty] )).item(0).membervalue ) -[b] error[/b]

Do you know how I can do it?

thanks

RWrigley

The closingperiod function will give you the "last" member of the specified time level, but that may not be accurate if your cube has forward looking dates:

select
closingperiod ([Date].[Calendar].[Date]) on Rows,
[Measures].[Internet Sales Amount] on Columns
from [Adventure Works]

A more robust solution is to generate a set filtered on a measure that you know only has values for current dates, and then take the last member of that:

select
tail(filter([Date].[Calendar].[Date],[Measures].[Internet Sales Amount] <> NULL),1) on Rows,
[Measures].[Internet Sales Amount] on columns
from [Adventure Works]

A similar approach is to define an attribute flag in your time dimension that will indicate the current day. However, this is only practical if you're updating the cube every day.

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RWrigley

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