adding foci points to my hyperbola in Matlab

Posted on 2009-03-30
Medium Priority
Last Modified: 2016-02-10
Please find the matlab code below;

ok... I figured out that my foci points : d=+/- sqrt(a) +sqrt(b)
Is this ok?

and how do I add this to my code below

thanks in advance
% Program to plot the hyperbola
% y^2/a^2 - x^2/b^2 = 1
% The hyperbolae are open up/down, so that x is the independent variable
% for plotting. (Using the form x^2/a^2 - y^2/b^2 = 1 requires that y be
% the independent variable, which is awkward programming-wise.)
clear % all variables
figure(1), hold off % start a new figure
set(gca,'FontSize',14) % adjust fontsize
xmax = 30; ymax = 20;
x = linspace(-xmax,xmax,1001); % array of x values for plot : This function generates vector with 1001 points equally distributed between -xmax and xmax. 
                                %1001 is probably to have 500 points on one side (>0), 500 on another side (<0) and to include 0 itself. So you will have 
                                 %more natural numbers. 
a = 5; b = 3;
y=sqrt(((x.^2)./(b^2)+1).*a^2); % corresponding y values
hold on % add to current plot
plot(x,-y) % Plot other half of hyperbola
axis([-xmax xmax -ymax ymax]) % specify axis limits
title(['Hyperbola $y^2/a^2 - x^2/b^2 = 1$; $a$ = ', num2str(a), ...
', $b$ = ', num2str(b),'; (WR 1/21/08)'],'Interpreter','latex')
% Add axes
plot([0 0],[-ymax ymax],'k') % y axis (black line - k)
plot([-xmax xmax],[0 0],'k') % x axis
% Program to plot the elipse
% y^2/a^2 - x^2/b^2 = 1
y=sqrt(((-x.^2)./(b^2)+1).*a^2); % corresponding y values
hold on % add to current plot
plot(x,-y) % Plot other half of elipse
axis([-xmax xmax -ymax ymax]) % specify axis limits
title(['Hyperbola and elipse $y^2/a^2 + x^2/b^2 = 1$;$y^2/a^2 - x^2/b^2 = 1$; $a$ = ', num2str(a), ...
', $b$ = ', num2str(b),';'],'Interpreter','latex')
% Add axes
plot([0 0],[-ymax ymax],'k') % y axis (black line - k)
plot([-xmax xmax],[0 0],'k') % x axis

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Question by:jtiernan2008
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LVL 15

Expert Comment

ID: 24023169
Are those points at x=0? Then you can add them with
plot([0 0], [-sqrt(a)+sqrt(b) sqrt(a)+sqrt(b)],'o')

Are you sure it's correct? May be this?
plot([0 0], [-sqrt(a^2+b^2) sqrt(a^2+b^2)],'ro')

Or this?
plot([0 0], [-a a],'go')

Please define what are foci points?


Author Comment

ID: 24023262

foci is focus plural

I actually done as follows.

text(0,f1,'\leftarrow +d')
text(0,f2,'\leftarrow -d')

Is this correct?
LVL 15

Accepted Solution

yuk99 earned 2000 total points
ID: 24023521
If c^2=a^2+b^2, then c=+-sqrt(a^2+b^2). Is it focus points?

I'd also add VerticalAlignment and HorizontalAlignment to make sure the pointers positions are closest.

plot([0 0],[f1 f2],'.')
text(0,f1,'\leftarrow +d','VerticalAlignment','middle','HorizontalAlignment','left')
text(0,f2,'\leftarrow -d','VerticalAlignment','middle','HorizontalAlignment','left')

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LVL 15

Expert Comment

ID: 24023528
Or f2=-f1;

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