Creating XML file in Winforms to Load into a DataGrid in C# part 1

Posted on 2009-03-30
Last Modified: 2012-05-06
I need to write a function in C# that checks if an XML file exists at a certain path. If the file exists I need to append child nodes(person) to the XML file and save it.  If it doesn't exists, I need to create The XML file , then append the child nodes(person) to this and save it.  I will later load the XML file using another form that contains a DataGrid so the file can be viewed in a grid style layout.  How would I write a function to do this? The part 2 of this question I will put in a separate question as far as loading the DataGrid. After a solution is found to this one. Thanks for any help in advance.
<Family> // root 




<address> 542 bell south</address>





<address> 508 bell south</address>



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Question by:encoredatas
  • 3
LVL 12

Expert Comment

ID: 24024558
Something like...          

            XmlDataDocument doc;

            doc = new XmlDataDocument();

           bool exists = true;





            catch (System.IO.FileNotFoundException fe)


                // File not found

                exists = false;

                doc.CreateElement( "Family" );



            XmlDocument doc2 = new XmlDocument();

            doc2.LoadXml( "<person......");

            doc.AddChild ( doc2.DocumentElement );

           doc.Save ();


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LVL 29

Accepted Solution

anarki_jimbel earned 500 total points
ID: 24025584
Try this:
            string filename = "family.xml";

            bool exists = File.Exists(filename);

            XmlDocument doc = new XmlDocument();

            if (exists)






                XmlElement family = doc.CreateElement("family");



                XmlElement person = doc.CreateElement("person");

                XmlElement firstname = doc.CreateElement("firstname");

                XmlElement lastname = doc.CreateElement("lastname");

                XmlElement address = doc.CreateElement("address");





                firstname.InnerText = "Elvis";

                lastname.InnerText = "Presley";

                address.InnerText = "Hollywood";


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LVL 29

Expert Comment

ID: 24025593
I tested the code and it works. However it does not validates the xml. If xml is not valid - we'll get an error. So some additional precautions should be taken. E.g. put doc.Load(filename)  into try-catch
LVL 29

Expert Comment

ID: 24025725
Bonus :)

Really, I probably can give you a solution to part 2. The easiest way to display your xml in a grid is to use a dataset. If you want to just display (not edit) - set e.g. datagridview1.editmode = editprogrammatically
        private void button1_Click(object sender, EventArgs e)


            string filename = "family.xml";

            DataSet ds = new DataSet();


            this.dataGridView1.DataSource = ds.Tables[0];


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Author Closing Comment

ID: 31564600
Thanks so much this work like a charm and saved me a lot of time. P. S Thanks for the bonus.

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