Solved

posting variable into function doesnt work

Posted on 2009-03-31
2
186 Views
Last Modified: 2012-05-06
hi all posting my variable $error into the showform function doesnt seem to work, can anyone tell me why?

thanks
<?php 

function ShowForm($error) {

?>

<div class="text">

<h2>Staff Log In </h2>

<form id="form" method="post" action="/includes/login.php" class="menu">

  <table width="544">

     <tr>

       <td>Username:</td>

      <td><input name="txtUserName" type="text" size="20"  /></td>

      <td rowspan="5">&nbsp;</td>

     </tr>

     <tr>

      <td>Password:</td><td><input name="txtPassword" type="password" size="20" /></td>

     </tr>

     <tr>

       <td>&nbsp;</td>

       <td><input name="submit" type="submit" value="Login" /></td>

     </tr>

      <tr>

        <td colspan="2"><?php echo $error; ?></td>

      </tr>

      <tr>

      <td colspan="2">Lost your password? <a href="/admin/lostpass.php">Click Here</a></td>

      </tr>

    </table>

</form>

</div>

<?php

}
 

switch(@$_GET["action"]) {

Case "adminonly":

include($_SERVER['DOCUMENT_ROOT'] . '/includes/connection.php');

include($_SERVER['DOCUMENT_ROOT'] . '/includes/header.php');

$error = '<span style="padding-top:30px; color:#FF0000; ">';

$error .= '<strong>Error:</strong><br /> You need to be a member of staff to access these pages.';

$error .= '</span>';

ShowForm();

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Question by:awilderbeast
2 Comments
 
LVL 142

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 24027283
change:
ShowForm();

into:
ShowForm($error);
0
 
LVL 1

Author Closing Comment

by:awilderbeast
ID: 31564746
ahhh yes how silly of me :)

thankyou :)
0

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