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Get Folder

Hey all, I'm trying check a file path and active a function.

I'm working with a Navigation bar and a Sub-navigation bar. At start the Sub Nav is turned off via css (display=none)

Want I want to do  is turn the subnav on depending on what channel (folder they are currently in).

Anybody have a idea on how I would check file paths and run the logic behind it? Any help would be great.

Thanks
0
rurth24
Asked:
rurth24
  • 3
1 Solution
 
Michel PlungjanIT ExpertCommented:
You mean something like

if (location.href.indexOf('home')!=1) document.getElementById('homeDiv').className='selected'
0
 
ziffgoneCommented:
Umm, try this.

Note: your id for each sub nav will need to be "sub_nav_%FOLDERNAME%", where %FOLDERNAME% is the name of the folder where this sub nav would be visible.


<script type="text/javascript">
function show SubNav(){
    var getFolder=new Array();
    getFolder=unescape(top.location.href).split('/');
    var folder=getFolder[getFolder.length-2];
    document.getElementById('sub_nav_%FOLDERNAME%').style.display='block';
}
window.onload=SubNav();
</script>

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0
 
ziffgoneCommented:
Sorry, that code should have been this:


<script type="text/javascript">
function show SubNav(){
    var getFolder=new Array();
    getFolder=unescape(top.location.href).split('/');
    var folder=getFolder[getFolder.length-2];
    document.getElementById('sub_nav_'+folder).style.display='block';
}
window.onload=SubNav();
</script>

Open in new window

0
 
ziffgoneCommented:
Darn, I must be tired. Just came off night shift :(

Disregard the above two examples and go with this:


<script type="text/javascript">
function showSubNav(){
    var getFolder=new Array();
    getFolder=unescape(top.location.href).split('/');
    var folder=getFolder[getFolder.length-2];
    document.getElementById('sub_nav_'+folder).style.display='block';
}
window.onload=showSubNav();
</script>

Open in new window

0
 
rurth24Author Commented:
Thanks Ziff/mplung...

I'm going to test this out shortly and let you know the outcome...

Thanks again.
0
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