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No application is associated with the specified file for this operation

mannevenu
mannevenu asked
on
1,988 Views
Last Modified: 2012-06-21
I am working on a web application and in that i have a small functionality to upload files to web server. As per the functionality user can upload file to webserver and after uploading can view the uploaded file.
the code for viewing is given below
protected void TreeView1_SelectedNodeChanged(object sender, EventArgs e)
    {              
   
        try
        {
           
            SelectMaster SelectMaster = new SelectMaster();
            string qry = "select Content_Id,Record_Type,Description from Admn_Course_Organization where Id='" + TreeView1.SelectedNode.Value + "' ";
            DataTable dt_Fill_TV = BusinessLayer.SelectMaster.GetDataTable(Session["ConStr"].ToString(), qry);
            string cid = dt_Fill_TV.Rows[0][0].ToString();
            string recort_type = dt_Fill_TV.Rows[0][1].ToString();
            string desc = dt_Fill_TV.Rows[0][2].ToString();
            if (recort_type.ToString().Equals("OPT"))
            {
                txtdesc.Visible = true;
                txtdesc.Text = desc.ToString();
 
            }
           
            else
            {
                txtdesc.Visible = false;
                txtdesc.Text = "";
                string qry1 = "select File_Path  from Admn_Content_Mast where Id='" + cid.ToString() + "'";
                DataTable dt_Fill_TV1 = BusinessLayer.SelectMaster.GetDataTable(Session["ConStr"].ToString(), qry1);
                string path = dt_Fill_TV1.Rows[0][0].ToString();
 
              
                 
                string strPath = Server.MapPath("..\\Head_Office_Content") + "\\" +path.ToString();
                if (File.Exists(strPath))
                {
                    System.Diagnostics.Process myProcess = new System.Diagnostics.Process();
                    myProcess.EnableRaisingEvents = false;
                    myProcess.StartInfo.FileName = strPath;
                    myProcess.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Maximized;
                    myProcess.Start();
                }
                else
                {
                    string strMsg = "No file to view.";
 
                    Label lbl = new Label();
 
                    lbl.Text = ("<script language=\'javascript\'>"
 
                    + (Environment.NewLine + ("window.alert(" + ("\'"
                    + (strMsg + ("\'" + ")</script>"))))));                  
                    Page.Controls.Add(lbl);
 
                }
            }

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Most Valuable Expert 2012
Top Expert 2014

Commented:
The code you have written to open the file would execute on the server and the opened file would not be visible to the client. May be you want to show them some thumbnail of the image or something.
Top Expert 2009

Commented:
You're getting that error because your server does not know how to open one of the file.

System.Diagnostics.Process myProcess = new System.Diagnostics.Process();
myProcess.EnableRaisingEvents = false;
myProcess.StartInfo.FileName = strPath;
myProcess.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Maximized;
myProcess.Start();

Say the file name is c:\temp\Music\playlist.dat. When you run this, the server does not know what application to open this file with and that's when it says:

No application is associated with the specified file for this operation

Author

Commented:
So please give me the solution for this problem..urgent
Top Expert 2009

Commented:
CERTIFIED EXPERT
Most Valuable Expert 2012
Top Expert 2014
Commented:
This one is on us!
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Author

Commented:
thank u sir its help ful

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