Looking for a way to test network capacity, accounting for swicth / router response times etc


I've been tasked with writing a test spec for a project with applications spanning several geographic locations, and comprising multiple LANs, using a combination of TCP/IP and serial comms.

I am not a comms expert, but I think I know enough to get by.

What I want is a way of calculating the maximum time that should be allowed for two applications on a network to communicate a certain amount of data.

I'm planning so far on using some batch files with ping commands, ideally I'd like to say:

"We need to be able to send X1 amount of bytes in X2 amount of seconds, therefore, tests require a response to a Ping of 50000 bytes in X3 milliseconds."

If I know X1 and X2, do you think this is a reliable way of working X3?


I hope that makes sense, any help appreciated.



LVL 2
CognizeAsked:
Who is Participating?
 
Roachy1979Commented:
You can monitor round trip times, test connectivity and get good reporting out of Nagios....in terms of measuring bandwidths you could also use iPerf...you would need to install it at the source and destination...but with these tools you should be able to get the data you need

http://www.nagios.org/

http://en.wikipedia.org/wiki/Iperf



0
 
Hendrik WieseInformation Security ManagerCommented:
Hi,

You could try and use the following open source application to monitor the line while you push the data through: http://www.ethereal.com/

Hope it helps.
0
 
sda100Commented:
I use Nagios - it scales quite well, but if you want a serious solution take a look at OpenNMS - both of which are free.

With regard to making calculations using ping as a guide... it's not a good idea - most of the time 'pings' are given a very low traffic priority so will not necessarily give you accurate results.

Steve :)
0
 
CognizeAuthor Commented:
Thanks - Iperf was the best solution in the end.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.