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how to init dialog controls and also use DoModal()

Posted on 2009-04-03
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Last Modified: 2013-11-20
Hi, i like to use dialog templates from the resources, but don't want to add classes for each new dialog.
For example, i have a CListCtrl that is empty. I want it to be filled with data, before it's shown to the user.
The DoModal() creates the dialog itself, and so it doesn't allow me to do any initialization.

So I went to use the callback procedure provided by DialogBox() / CreateDialog(). But this doesn't work. please see code below (1)
Next thing I tried using CDialog::Attach(). But then the DoModal() raises exceptions. please see (2)

Can you experts please give me a tip -

--> I want to avoid creating derived CDialog classes for each resource template each time
AND keep modal behaviour
AND  initialize dialog controls

- Is it possible ? Thanks very much experts!


// callback -------------------------------------------------------------------------------------------

INT_PTR CALLBACK DlgProc(HWND hwndDlg, UINT uMsg, WPARAM wParam, LPARAM lParam)

{

switch(uMsg)

    {

	case WM_INITDIALOG:

	{

                       // init controls ...

                       return TRUE;

                }

return FALSE;

}

// attempt 1 -------------------------------------------------------------------------------------------

DialogBox(::GetModuleHandle(NULL), MAKEINTRESOURCE(IDD_MYDIALOG), AfxGetMainWnd()->m_hWnd, (DLGPROC)DlgProc);

 

// attempt 2 -------------------------------------------------------------------------------------------

HWND hDlg = CreateDialog(::GetModuleHandle(NULL), MAKEINTRESOURCE(IDD_MYDIALOG), AfxGetMainWnd()->m_hWnd, (DLGPROC)DlgProc);

if(hDlg)

{

CDialog dlg;

if(dlg.Attach(hDlg))

	{

	int retval = dlg.DoModal();

	dlg.Detach();

	}

}

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Question by:stev75
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9 Comments
 
LVL 19

Expert Comment

by:alb66
Comment Utility
You must do the controls initialization in OnInitDialog() function.

OnInitDialog is the default handler for WM_INITDIALOG message
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LVL 19

Expert Comment

by:alb66
Comment Utility
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Author Comment

by:stev75
Comment Utility
Thanks, the question is>
If there's a way to use something like PreTranslate message or a Hook for my dialog instance, that is NOT a CDialog derived object ?
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Accepted Solution

by:
alb66 earned 250 total points
Comment Utility
You can derive a class from CDialog and pass the template to it

class CYourDialog : public CDialog
{
public:
   CYourDialog( UINT nIDTemplate, CWnd* pParentWnd = NULL );

   virtual BOOL OnInitDialog();
}

CYourDialog::CYourDialog( UINT nIDTemplate, CWnd* pParentWnd ) <--- pass the template here
   : CDialog( nIDTemplate, pParentWnd  )
{
}

BOOL CYourDialog::OnInitDialog()
{
   Dialog::OnInitDialog();

   // initialize controls here
   ....
}
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Author Comment

by:stev75
Comment Utility
yes, i thought of a more elegant way, but it may be that it's the only way
0
 

Author Closing Comment

by:stev75
Comment Utility
i was way too fast with my previous comment (see below)... in fact, it IS elegant, since it is a good way of constructing the object and very short piece of code ! Thanks !!
0
 
LVL 44

Expert Comment

by:AndyAinscow
Comment Utility
Two points - the first you might have realised, its unclear from your comment.

1)  As alb66 says the OnInitDialog is the place to do initialisation of controls - it is called BEFORE the dialog is displayed so you can fill the controls there.

2) Maybe this class layout is useful.
class CMyBaseDialog : CDialog
class CMyDerivedDialog1 : CMyBaseDialog
class CMyDerivedDialog2 : CMyBaseDialog
...

Then you can use virtual functions for stuff in the derived classes and have the common code in the CMyBaseDialog class.
0
 

Author Comment

by:stev75
Comment Utility
Hi Andy,
2) the "one-level" architecture fits my needs. If you derive another class from your already CDialog -derived class, it would make sense if you want to have  fonts / colours for each dialog, which will be set in the base and each derived will automatically have it.
the point is, when you work with visual studio, and you design you're dialog VISUAL, you will get a new header and cpp file each time, generated by visual studio. I'm going to not use the generated stuff anymore, to have shorter and clearer implementation. This idea came up when I read the comment from alb66. I also think, this will speed up compilation time.
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Expert Comment

by:AndyAinscow
Comment Utility
you can still use the wizard generated files.
Consider - you make a new dialog in resource editor, create a new class for it eg. CMyNewDialog.  Now the wizard generates a cpp and h file with CMyNewDiaog based on CDialog.  In these two (cpp , h) files do a gobal find/replace with CDialog changed to CBaseDialog (or whatever the common class is called).  Finished - you now have the common code linked up.
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