Solved

Form Checkboxes Dynamically returned

Posted on 2009-04-06
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Last Modified: 2012-05-06
Hi Experts,

I have a form which I have a number of checkboxes for as search criteria for cars, rather than manually insert the checkboxes I am pulling them from my database so it returns checkboxes like:-

Vauxhall
Ford
Seat

 etc etc

I originally named the checkboxes a value (vehicles) but when returning the results of the selected vehicles it only returns the latest selection.

I have given my checkbox name and values my vehicleid to identify the selections but can anyone help me as to how to get all the id's selected in a built up string with comma's so something like this:-

1,2,3 (1,2,3 being the vehicle id) so I can use this string in my SQL statement.

Thanks
Tim
The code:-
$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
$sqlcount=mysql_num_rows($sqlresult);
 
 
The checkboxes:-
while($vehiclelist=mysql_fetch_array($sqlresult,MYSQL_NUM))
{
echo '<input type="checkbox" name="'.$vehiclelist[0].'" value="'.$vehiclelistt[0].'" />'.$vehiclelist[1].'<br/>';
}

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Question by:EzEApostle
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7 Comments
 
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Expert Comment

by:QualitySoftwareDevelopment
ID: 24076806
I'm not quite sure on what you need?! ... do you want the boxes to be checked or do you want to pull out a list with only the selected boxes?
0
 
LVL 1

Author Comment

by:EzEApostle
ID: 24076857
On the user filling out the search form I need the ID's (name) of the checkboxes that were selected :) by default they're all unselected
0
 
LVL 3

Expert Comment

by:QualitySoftwareDevelopment
ID: 24076953
Ok, i think there is a smarter way retrieving the content of the $_post, but the follwing should work
$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
 
$sqlnew='SELECT vehicle_id, display_name FROM vehicles WHERE ';
$firstruntrough=0;
 
while($vehiclelist=mysql_fetch_array($sqlresult))
{
   if($_POST["yourchecknames"]==1){
      if($firstrunthrough==0){
         $firstrunthrough=1;
         $sqlnew.="vehicle_id = $_POST["yourcheckvalue"] ";
      } else {
         $sqlnew.="OR vehicle_id = $_POST["yourcheckvalue"] ";
      }
   }
}

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Author Comment

by:EzEApostle
ID: 24076996
I dont think that will work because $_POST["yourchecknames"] is set to different ID's i.e. the Vehicle ID
0
 
LVL 3

Expert Comment

by:QualitySoftwareDevelopment
ID: 24077025
Ok then this should work
$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
 
$sqlnew='SELECT vehicle_id, display_name FROM vehicles WHERE ';
$firstruntrough=0;
 
while($vehiclelist=mysql_fetch_array($sqlresult))
{
   if($_POST["yourchecknames"] != 0){
      if($firstrunthrough==0){
         $firstrunthrough=1;
         $sqlnew.="vehicle_id = $_POST["yourchecknames"] ";
      } else {
         $sqlnew.="OR vehicle_id = $_POST["yourchecknames"] ";
      }
   }
}

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0
 
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Author Comment

by:EzEApostle
ID: 24077565
Again, I can't see it working because, this value $_POST["yourchecknames"] isn't a single value but many

I refer to my previous statement:-
echo '<input type="checkbox" name="'.$vehiclelist[0].'" value="'.$vehiclelistt[0].'" />'.$vehiclelist[1].'<br/>';
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Accepted Solution

by:
EzEApostle earned 0 total points
ID: 24085006
I've fixed it myself


			$sql='SELECT vehicle_id, display_name FROM vehicles';
			$sqlresult=mysql_query($sql);
			$sqlcount=mysql_num_rows($sqlresult);
			
				while($vehiclelist=mysql_fetch_array($sqlresult,MYSQL_NUM))
				{				
					for ($i=0; $i <= $sqlcount; ++$i) {
					   if(isset($_POST[''.$vechiclelist[$i].''])) {echo $_POST[''.$vehiclelist[$i].''].',';}
					}
				}				

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