asked on

Form Checkboxes Dynamically returned

Hi Experts,

I have a form which I have a number of checkboxes for as search criteria for cars, rather than manually insert the checkboxes I am pulling them from my database so it returns checkboxes like:-

Vauxhall
Ford
Seat

etc etc

I originally named the checkboxes a value (vehicles) but when returning the results of the selected vehicles it only returns the latest selection.

I have given my checkbox name and values my vehicleid to identify the selections but can anyone help me as to how to get all the id's selected in a built up string with comma's so something like this:-

1,2,3 (1,2,3 being the vehicle id) so I can use this string in my SQL statement.

Thanks
Tim

The code:-
$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
$sqlcount=mysql_num_rows($sqlresult);
 
 
The checkboxes:-
while($vehiclelist=mysql_fetch_array($sqlresult,MYSQL_NUM))
{
echo '<input type="checkbox" name="'.$vehiclelist[0].'" value="'.$vehiclelistt[0].'" />'.$vehiclelist[1].'<br/>';
}

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QualitySoftwareDevelopment

I'm not quite sure on what you need?! ... do you want the boxes to be checked or do you want to pull out a list with only the selected boxes?

EzEApostle

ASKER

On the user filling out the search form I need the ID's (name) of the checkboxes that were selected :) by default they're all unselected

QualitySoftwareDevelopment

Ok, i think there is a smarter way retrieving the content of the $_post, but the follwing should work

$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
 
$sqlnew='SELECT vehicle_id, display_name FROM vehicles WHERE ';
$firstruntrough=0;
 
while($vehiclelist=mysql_fetch_array($sqlresult))
{
   if($_POST["yourchecknames"]==1){
      if($firstrunthrough==0){
         $firstrunthrough=1;
         $sqlnew.="vehicle_id = $_POST["yourcheckvalue"] ";
      } else {
         $sqlnew.="OR vehicle_id = $_POST["yourcheckvalue"] ";
      }
   }
}

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EzEApostle

ASKER

I dont think that will work because $_POST["yourchecknames"] is set to different ID's i.e. the Vehicle ID

QualitySoftwareDevelopment

Ok then this should work

$sql='SELECT vehicle_id, display_name FROM vehicles';
$sqlresult=mysql_query($sql);
 
$sqlnew='SELECT vehicle_id, display_name FROM vehicles WHERE ';
$firstruntrough=0;
 
while($vehiclelist=mysql_fetch_array($sqlresult))
{
   if($_POST["yourchecknames"] != 0){
      if($firstrunthrough==0){
         $firstrunthrough=1;
         $sqlnew.="vehicle_id = $_POST["yourchecknames"] ";
      } else {
         $sqlnew.="OR vehicle_id = $_POST["yourchecknames"] ";
      }
   }
}

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EzEApostle

ASKER

Again, I can't see it working because, this value $_POST["yourchecknames"] isn't a single value but many

I refer to my previous statement:-
echo '<input type="checkbox" name="'.$vehiclelist[0].'" value="'.$vehiclelistt[0].'" />'.$vehiclelist[1].'<br/>';

ASKER CERTIFIED SOLUTION

EzEApostle

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