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Solved

Why the image is not echoed?

Posted on 2009-04-06
6
Medium Priority
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183 Views
Last Modified: 2012-05-06
here image is not shown why ?

<?php
echo $_POST['image'];
?>

<form action="1.php" method="post" name="form"  enctype="multipart/form-data">
<input type="file" name="image" id="image" />
<input type="submit">
</form>
0
Comment
Question by:designersx
[X]
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6 Comments
 
LVL 8

Expert Comment

by:mostart
ID: 24077072
because file uploads are handled by other POST variables:

try to echo these:

$_FILES['image']['name'] <- filename on client machine
$_FILES['image']['type']  <- mime-type
$_FILES['image']['size'] <- size
$_FILES['imgae']['tmp_name'] <- name on server

more info here:

http://de.php.net/manual/en/features.file-upload.post-method.php
0
 
LVL 14

Expert Comment

by:shobinsun
ID: 24077083
Use :

<?php
echo $_FILES['image'];
?>

<form action="1.php" method="post" name="form"  enctype="multipart/form-data">
<input type="file" name="image" id="image" />
<input type="submit">
</form>
0
 
LVL 14

Accepted Solution

by:
shobinsun earned 200 total points
ID: 24077128
Hello,

Use for printing the name of the file:

<?php
echo $_FILES['image']['name'];
?>

<form action="1.php" method="post" name="form"  enctype="multipart/form-data">
<input type="file" name="image" id="image" />
<input type="submit">
</form>
0
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LVL 14

Expert Comment

by:shobinsun
ID: 24077210
Hello,

<?php
$source = $_FILES['image']['name'];
$target = './'.$_FILES['image']['name'];
move_uploaded_file($source, $target);

echo "image: <img src='./".$target."'><br>";

?>

To display the image that you have uploaded

Regards.
0
 

Author Comment

by:designersx
ID: 24084035
ok thanks.
0
 
LVL 8

Expert Comment

by:mostart
ID: 24085498
oh come on this is not fair. I was the first who answered and I gave you the same and even some additional information. The answer you accepted did only repeat parts of what I already wrote before, so at least you could split the points.
Its not fun helping people if they act like this, don't you think so ?
0

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