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How to list next 12 months

Posted on 2009-04-07
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Last Modified: 2013-12-13
I had someone write up this code for me. It works great except for when it displays the second line of the next twelve months, it starts that line with a |
So it looks like
May 09 | Jun 09 | Jul 09 | Aug 09 | Sep 09 | Oct 09
| Nov 09 | Dec 09 | Jan 10 | Feb 10 | Mar 10 | Apr 10

How can I remove the | before the start of the second line so it looks like
May 09 | Jun 09 | Jul 09 | Aug 09 | Sep 09 | Oct 09
Nov 09 | Dec 09 | Jan 10 | Feb 10 | Mar 10 | Apr 10

<?php
	for ($i = 0; $i < 12; $i++)
								{
								$echo_date = date("M y", mktime(0, 0, 0, date("m") + $i + 1, 1, date("Y")));
	$link_date = date("mY", mktime(0, 0, 0, date("m") + $i + 1, 1, date("Y")));
	echo "<a href=\"happening.php?monthdisplay=$link_date\"><font class=\"style8\">	$echo_date</font></a>\n";
								if ($i == 5)
								{
									echo "<br />\n";
								}
								if ($i < 11)
								{
									echo " | ";
								}
	}
							?>

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Question by:katlees
  • 3
5 Comments
 
LVL 12

Expert Comment

by:adrian_brooks
ID: 24088500
change this;

if ($i < 11)
{
  echo " | ";
}

to this;

if ($i < 11 && $ != 5)
{
  echo " | ";
}
0
 

Author Comment

by:katlees
ID: 24088567
I get Parse error: syntax error, unexpected T_IS_NOT_EQUAL, expecting T_VARIABLE or '$' in /home/visitmit/public_html/happening.php on line 108

That line is
if ($i < 11 && $ != 5)
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LVL 12

Accepted Solution

by:
adrian_brooks earned 500 total points
ID: 24088682
Ooops! Sorry...typo

if ($i < 11 && $i != 5)

~A~
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LVL 14

Expert Comment

by:shobinsun
ID: 24088743
Hello,

Use this code:


<?php
        for ($i = 0; $i < 12; $i++)
                                                                {
                                                                $echo_date = date("M y", mktime(0, 0, 0, date("m") + $i + 1, 1, date("Y")));
        $link_date = date("mY", mktime(0, 0, 0, date("m") + $i + 1, 1, date("Y")));
        echo "<a href=\"happening.php?monthdisplay=$link_date\"><font class=\"style8\"> $echo_date</font></a>\n";
                                                                if ($i == 5)
                                                                {
                                                                        echo "<br />\n";
                                                                }
                                                                if ($i < 11 && $i!=5)
                                                                {
                                                                        echo " | ";
                                                                }
        }
                                                        ?>

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0
 
LVL 12

Expert Comment

by:adrian_brooks
ID: 24088820
shobinsun, why would you post the exact same solution I just provided?

~A~
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